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2 years ago

(I is confusion)What fraction of an hour is 35 minutes?give your answer in simplest form

Mathematics

1 answer:

lesya [120]2 years ago

5 0

Answer
1 hour=60 minutes
Fraction= 35/60= 7/12
So your answer would be 7/12 :)

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There is a 25% chance that Dane will make a three-point shot during a basketball game. A random-number generator generated 10 se

makvit [3.9K]

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Step-by-step explanation:

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3 years ago

NEED HELP IN FINDING AREA

Aliun [14]

Answer:

809 km²

Step-by-step explanation:

I can split this into 3 rectangles. One is 25 by 17, another is 24 by 13, and the last one is 6 by 12. (I had gotten 13 for the second rectangle because 25 - 12 = 13.)

(25 * 17) + (24 * 13) + (6 * 12) {17 is the first number after a multiple of 4 (16). As a result, 25 by 17 will end in "25." 25 by 17 is 425.}

425 + (24 * 13) + (6 * 12) {24 by 13 is 312.}

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425 + 312 + 72 {From left to right, add 425, 312, and 72 to get 809}

737 + 72

809 km²

The area of this figure is 809 km².

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3 years ago

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MrMuchimi

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3 years ago

Find the exact values of sin2 θ for cos θ = 3/18 on the interval 0° ≤ θ ≤ 90°

mote1985 [20]

Answer:

$sin(2\theta)=\frac{\sqrt{35} }{18}$

Step-by-step explanation:

Recall the formula for the sine of the double angle:

$sin(2\theta)=2*sin(\theta)*cos(\theta)$

we know that $cos(\theta)=\frac{3}{18}$ , and that $\theta$ is in the interval between 0 and 90 degrees, where both the functions sine and cosine are non-negative numbers. Based on such, we can find using the Pythagorean trigonometric property that relates sine and cosine of the same angle, what $sin(\theta)$ is:

$cos^2(\theta)+sin^2(\theta)=1\\sin^2(\theta)=1-cos^2(\theta)\\sin(\theta)=\sqrt{1-cos^2(\theta)} \\sin(\theta)=\sqrt{1-(\frac{3}{18} )^2}\\sin(\theta)=\sqrt{1-\frac{9}{324} }\\sin(\theta)=\sqrt{\frac{324-9}{324} }\\sin(\theta)=\sqrt{\frac{315}{324} }\\\\sin(\theta)=\frac{3}{18}\sqrt{35 }$

With this information, we can now complete the value of the sine of the double angle requested:

$sin(2\theta)=2*sin(\theta)*cos(\theta)\\sin(2\theta)=2*\frac{3}{18} \,\sqrt{35} \,\frac{3}{18}\\sin(2\theta)=\frac{2*3*3}{18*18}\,\sqrt{35} \\sin(2\theta)=\frac{\sqrt{35} }{18}$

6 0

3 years ago

Can somebody help me with this problem

lesya [120]

3/5 If I'm not mistaken.

7 0

3 years ago

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