What is the density of 9 cm³ gold cube with 450 g in a mass?
1 answer:
Answer:
Answer is 50g/cm^3
Step-by-step explanation:
soln,
Volume of the gold cube = 9 cm^3
Mass of the gold cube = 450 g
now,
density= mass/volume
=450 / 9
=50 g/cm^3
{Therefore, the density of the gold cube is 50 g/cm^3.}
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