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2 years ago

3^(4x-5) = (1/27)^(2x+10) show your work

Mathematics

1 answer:

sladkih [1.3K]2 years ago

4 0

Answer:

3^4x-5=1/27^2x+10

We move all terms to the left:

3^4x-5-(1/27^2x+10)=0

Domain of the equation: 27^2x+10)!=0

x∈R

We get rid of parentheses

3^4x-1/27^2x-10-5=0

We multiply all the terms by the denominator

3^4x*27^2x-10*27^2x-5*27^2x-1=0

Wy multiply elements

81x^6-270x^2-135x^2-1=0

We do not support expression: x^6

Step-by-step explanation:

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Data:
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Use substitution to solve the system of equations Y+x=3 Y=1.5x+1

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The solution to given system of equation is (x, y) = (0.8, 2.2)

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Given system of equations are:

y + x = 3 --------- eqn 1

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Substitute eqn 2 in eqn 1

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Step-by-step explanation:

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