Magnitude of the net displacement: 7.0 miles
Step-by-step explanation:
In order to find the total displacement of the man, we have to resolve each displacement along the x- and y- direction.
Taking x as positive x direction and y as positive north direction:
- The first motion is 3 miles due east, so
- The second motion is 5 miles at 
east of north, so:
So the components of the net displacement are
And so the magnitude of the net displacement is
So, he is 7.0 miles far from the house.
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Answer:
Answer: 84 meters squared. (i.e. 84m^2).
Step-by-step explanation:
Area of the path = total area of path and plot - plot area only
First, let’s find the area of the plot:
20m x 20m = 400m^2
The path is 1m wide and runs all the way around, so, it describes an ‘outer square’ of 22m x 22m (2 x 1m larger because there are 1m of the path on each side).
The area of this ‘outer square’ is equivalent to the ‘total area of path and plot’
22m x 22m = 484m^2
So:
Area of the path = total area of path and plot - plot area only
= 484 - 400 = 84m^2
Answer:
m∠R = 112°
m∠S = 112°
m∠T = 68°
Step-by-step explanation:
Quadrilateral QRST is a cyclic quadrilateral.
A <u>cyclic quadrilateral</u> is a quadrilateral drawn inside a circle where every vertex touches the circumference of the circle.
The <u>opposite angles</u> in a cyclic quadrilateral sum to 180°.
⇒ m∠Q + m∠S = 180°
⇒ m∠R + m∠T = 180°
Given:
- m∠Q = 68°
- m∠R = (3x + 40)°
- m∠T = (5x - 52)°
<u>Measure of angle Q</u>
⇒ m∠Q + m∠S = 180°
⇒ 68° + m∠S = 180°
⇒ m∠S = 180° - 68°
⇒ m∠S = 112°
<u>Measure of angles R and T</u>
⇒ m∠R + m∠T = 180°
⇒ (3x + 40)° + (5x - 52)° = 180°
⇒ )8x -12)° = 180°
⇒ 8x° = 192°
⇒ x = 24
Substituting the found value of x into the expressions for angles R and T:
⇒ m∠R = (3(24) + 40)°
⇒ m∠R = 112°
⇒ m∠T = (5x - 52)°
⇒ m∠T = 68°
0.12 because it equals to 12% where 1.2% equals to 0.012
Answer:
BCE
Step-by-step explanation:
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