Answer:
Move the decimal two places to the right and add a percent sign.
Step-by-step explanation:
.15= 15%
1.25= 125%
.06= 6.0, or 6%
Answer:
x = -3, 4/5
Step-by-step explanation:
To factor the equation, you need to find factors of (5)(-12) that have a sum of (+9).
(5)(-12) = -60 = 60(-1) = 30(-2) = 15(-4) = 12(-5) = 10(-6)
The factors 15 and -4 have a sum of 9, so we can factor the equation as ...
5x² +15x -4x -12 = 0
5x(x +3) -4(x +3) = 0 . . . . factor pairs of terms
(5x -4)(x +3) = 0
The solutions are the values of x that make these factors zero:
5x -4 = 0 ⇒ x = 4/5
x +3 = 0 ⇒ x = -3
The solutions are x = -3 or 4/5.
You have to check which of the following expressions is the rational exponent expression of third root of 4n, or mathematically, ![\sqrt[3]{4n} .](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B4n%7D%20.%20)
Consider all cases:
A. ![(4n)^3=4^3\cdot n^3=64n^3\neq\sqrt[3]{4n} .](https://tex.z-dn.net/?f=%20%284n%29%5E3%3D4%5E3%5Ccdot%20n%5E3%3D64n%5E3%5Cneq%5Csqrt%5B3%5D%7B4n%7D%20.%20%20)
B. ![3n^4\neq \sqrt[3]{4n} .](https://tex.z-dn.net/?f=%203n%5E4%5Cneq%20%5Csqrt%5B3%5D%7B4n%7D%20.%20%20)
C. quantity of 4n to the one third power is ![(4n)^{\frac{1}{3} }=\sqrt[3]{4n}](https://tex.z-dn.net/?f=%20%284n%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%3D%5Csqrt%5B3%5D%7B4n%7D%20)
(by the definition of rational power).
D. 4 times n to the one third power is ![4\cdot n^{\frac{1}{3} }=4\sqrt[3]{n}\neq \sqrt[3]{4n} .](https://tex.z-dn.net/?f=%204%5Ccdot%20n%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%3D4%5Csqrt%5B3%5D%7Bn%7D%5Cneq%20%5Csqrt%5B3%5D%7B4n%7D%20.%20%20)
Answer: correct choice is C.
3n+2n+4=9n+12
5n+4=9n+12
4-12=9n-5n
-8=4n
Divide both sides by 4
n=-2
We can write an equation to resemble the problem.
1160 = 170 + 50x
x equals the number of boxes he is carrying.
Solve for x.
1160 = 170 + 50x
990 = 50x
19.8 = x
We can't round up because that will be to much weight. So, we are going to round down.
19.8 -> 19
Therefore, the answer is 19.
Best of Luck!
