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2 years ago

14

there are 147 third grade students going to the theater. Each row at the theater has ten seats. How many rows of seats will the

third grade students fill?

1 answer:

givi [52]2 years ago

7 0

Answer:

157

Step-by-step explanation:

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2x (y^2+3)-5 (3+y^2)

Irina18 [472]

Use distributive property a(b + c) = ab + ac.

$2x(y^2+3)-5(3+y^2)=(2x)(y^2)+(2x)(3)+(-5)(3)+(-5)(y^2)\\\\=2xy^2+6x-15-5y^2$

3 0

3 years ago

According to a soccer coach, 75% of soccer players have had at least one sprained ankle. An athletic trainer would like to inves

Greeley [361]

Answer:

H0 : μ = 0.75

H1 : μ > 0.75

Step-by-step explanation:

Given :

Sample size, n = 125

x = 99

Phat = x / n = 99 / 125 = 0.792

Population proportion, P = 0.75

The hypothesis :

Null hypothesis :

H0 : μ = 0.75

Alternative hypothesis ;

Egates the null hypothesis ; since the sample proportion is greater than the the population proportion or claim "; then we use the greater than sign.

H1 : μ > 0.75

5 0

2 years ago

A car dealership sells SUVs and passenger cars . For a recent year, 80 more SUVs were sold than passenger cars. If a total of 51

MAVERICK [17]

Answer:

295 SUVs were sold, and 215 passenger vehicles.

Step-by-step explanation:

Let s and p represent the number of SUVs and p the number of passenger cars.

Then s = p + 80 and s + p = 510.

Substitute p + 80 for s in the second equation, obtaining:

p + 80 + p = 510, or:

2p = 430

Dividing both sides by 2 isolates p: p = 215.

Since s = p + 80, we add 80 to 215 here, obtaining s = 295.

295 SUVs were sold, and 215 passenger vehicles.

3 0

3 years ago

Triangle J'K'L' shown on the grid below is a dilation of triangle JKL using the origin as the center of dilation: Which scale fa

Free_Kalibri [48]

Triangle JKL has a base that is 1 unit long

Triangle J'K'L' has a base that is 3 units long

3 units / 1 unit = 3

The scale factor is 3.

7 0

3 years ago

Read 2 more answers

A civil engineer is analyzing the compressive strength of concrete. Compressive strength is normally distributed with A random s

wel

Answer:

95%: (3278.354 ; 3270.083)

99% : (3221.646 ; 3278.354)

Step-by-step explanation:

Given :

Sample size, n = 12

Mean, xbar = 3250

Sample standard deviation = √1000

The 95% confidence interval :

Mean ± Margin of error

Margin of Error = Tcritical * s/√n

Tcritical at 0.05, df=12-1 = 11 ;

Tcritical at 95% = 2.20

Hence,

Margin of Error = (2.20 * √1000/√12) = 20.083

Confidence interval : 3250 ± 20.083

Lower boundary = 3250 - 20.083 = 3229.917

Upper boundary = 3250 + 20.083 = 3270.083

2.)

The 99% confidence interval :

Mean ± Margin of error

Margin of Error = Tcritical * s/√n

Tcritical at 0.01, df=12-1 = 11 ;

Tcritical at 99% = 3.106

Hence,

Margin of Error = (3.106 * √1000/√12) = 28.354

Confidence interval : 3250 ± 28.354

Lower boundary = 3250 - 28.354 = 3221.646

Upper boundary = 3250 + 28.354 = 3278.354

3 0

3 years ago