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kolezko [41]
3 years ago
8

What is the answer for -3y+12=-48-3y+12=-48

Mathematics
1 answer:
Korvikt [17]3 years ago
4 0

-3y + 12 = -48     <em>subtract 12 from both sides</em>

-3y = -60     <em>divide both sides by (-3)</em>

<h3><em>y = 20</em></h3>
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A rectangle has a length of the cube root of 81 inches and a width of 3 to the 2 over 3 power inches. Find the area of the recta
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#1
A= \sqrt[3]{81}*3^{ \frac{2}{3} }= \sqrt[3]{3^4}*3^{ \frac{2}{3} } = 3^{ \frac{4}{3} }*3^{ \frac{2}{3} }=3^{ \frac{4}{3} + \frac{2}{3} }=3^2=9

9 inches squared


#2
\left( 5^{ \frac{3}{4} } \right)^{ \frac{2}{3} }=5^{ \frac{3}{4} *\frac{2}{3} }=5^{ \frac{1}{2} }= \sqrt{5}

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#3
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4 years ago
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5 0
3 years ago
Geometry will mark brainliest circles
Vladimir79 [104]

Answer:

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2. By solving the equation, we can find that x=8. Plugging in the value for arc CD's equation, you will find that it is equal to 77°.

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hodyreva [135]

Answer:

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Step-by-step explanation:

We know that

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  • \cos( \alpha )  =  \frac{side \: adjacent \: to \:  \alpha }{hypotenuse \: of \: traingle}
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where \alpha is an angle of a triangle.

In the triangle given above , \alpha = 45°. So,

1) \sin( 45)  =  \frac{16}{q}

=  >  \frac{1}{ \sqrt{2} }  =  \frac{16}{q}

=  > q = 16 \sqrt{2}

2) \tan(45)  =  \frac{16}{r}

=  > 1 =  \frac{16}{r}

=  > r = 16

8 0
3 years ago
Last month, Lloyd's Systems analyzed the project whose cash flows are shown below. However, before the decision to accept or rej
Radda [10]

Answer:

  C.  $9.04

Step-by-step explanation:

The net present value of a cash flow C in year n at some interest rate r is given by ...

  NPV = C·(1 +r)^(-n)

Adding the values of the different cash flows at the different interest rates, we get the results shown in the attached table. The NPV goes up by $9.04 when the cost of capital goes down.

_____

<em>Additional comment</em>

Neither WACC will cause this project to be rejected. If the WACC were to increase to 11.11%, then the project would have a zero return.

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3 years ago
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