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Fynjy0 [20]
3 years ago
8

Find the missing factor B that makes the equality true. 21y^4= (B) (7y^3)​

Mathematics
1 answer:
adelina 88 [10]3 years ago
8 0

Answer:

21y^4= B*7y^3

B=(21y^4)/(7y^3)

B=3y

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Can someone please help me with this question?
ryzh [129]

Answer: (3,2)

Step-by-step explanation:

4 0
3 years ago
Compute the difference quotient StartFraction f left parenthesis x plus h right parenthesis minus f left parenthesis x right par
kenny6666 [7]

Answer:

\dfrac{f(x+h) - f(x)}{h}=-8x-4h-3

Step-by-step explanation:

f(x)=-4x^2-3x-4

f(x+h)=-4(x+h)^2-3(x+h)-4

f(x+h)=-4(x^2+2xh+h^2)-3(x+h)−4

f(x+h)=-4x^2-8xh-4h^2-3x-3h-4

f(x+h) - f(x)=-4x^2-8xh-4h^2-3x-3h-4-(-4x2-3x-4)

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f(x+h) - f(x)=-8xh-4h^2-3h

f(x+h) - f(x)=h(-8x-4h-3)

\dfrac{f(x+h) - f(x)}{h}=\dfrac{h(-8x-4h-3)}{h}

\dfrac{f(x+h) - f(x)}{h}=-8x-4h-3

7 0
3 years ago
35/27 as a mixed number
sineoko [7]
8/27 would be the answer
5 0
3 years ago
Who can help me with this
Lady bird [3.3K]

Answer:

Growth

Step-by-step explanation:

Given

\frac{2}{3}(2.5)^x

Required

Growth or decay

The general form is:

y = ab^x

Such that:

b = rate

For b, we have the following conditions:

b > 1 ----- Growth

0 --- Decay

b = 1 ---- None

Compare \frac{2}{3}(2.5)^x to y = ab^x

b = 2.5

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3 0
3 years ago
What is the distance between the points (2,6) and (5,8)? Round to the
lidiya [134]

The distance between given points is 3.6 units.

Step-by-step explanation:

Given points are;

(2,6) and (5,8)

Here;

x_1=2\\y_1=6\\x_2=5\\y_2=8

Distance between two points is calculated by;

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\Distance = \sqrt{(5-2)^2+(8-6)^2}\\\\Distance = \sqrt{(3)^2+(2)^2}\\\\Distance = \sqrt{(9+4)}\\\\Distance = \sqrt{13}\\\\Distance=3.6\ units

The distance between given points is 3.6 units.

Keywords: distance, points

Learn more about distance at:

  • brainly.com/question/101683
  • brainly.com/question/103144

#LearnwithBrainly

8 0
3 years ago
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