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Ksju [112]
3 years ago
15

A 0.10 kg baseball travelling at 40 m s−1 hits straight back to the pitcher at 55 m s−1. The contact time is 0.01 seconds. What

is the change in momentum of the baseball? ​
Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0

Answer:

1.5 kgms⁻¹

Explanation:

Momentum can be defined as "<em>mass in motion</em>."  

The amount of momentum that an object has is dependent upon two factors

  • mass of the moving object  
  • speed of motiom 

when there is a change in the velocity , it creates a change in momentum also

when we consider that we can mathematically show this,In terms of an equation,

Change in momentum    (ΔΡ) = m(Δv)

where (Δv) - change in velocity

<em>(Δv) = final velocity - initial velocity</em>

Change in momentum (ΔΡ) = m(Δv)

                                             = 0.1×([55-40])

                                             = 1.5 kgms⁻¹

     

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Suppose 8.50 ✕ 10^5 J of energy are transferred to 1.63 kg of ice at 0°C. The latent heat of fusion and specific heat of water a
PolarNik [594]

Answer:

(a) 5.43 x 10⁵ J

(b) 3.07 x 10⁵ J

(c) 45 °C

Explanation:

(a)

L_{f} = Latent heat of fusion of ice to water = 3.33 x 10⁵ J/kg

m = mass of ice = 1.63 kg

Q_{f} = Energy required to melt the ice

Energy required to melt the ice is given as

Q_{f} = m L_{f}

Q_{f} = (1.63) (3.33 x 10⁵)

Q_{f} = 5.43 x 10⁵ J

(b)

E = Total energy transferred = 8.50 x 10⁵ J

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Using conservation of energy

E = Q_{f} + Q

8.50 x 10⁵ = 5.43 x 10⁵ + Q

Q = 3.07 x 10⁵ J

(c)

T₀ = initial temperature = 0°C

T = Final temperature

m = mass of water = 1.63 kg

c = specific heat of water = 4186 J/(kg °C)

Q = Amount of energy to raise the temperature of water = 3.07 x 10⁵ J

Using the equation

Q = m c (T - T₀)

3.07 x 10⁵ = (1.63) (4186) (T - 0)

T = 45 °C

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Answer:

Explanation:

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