Answer:
We cannot place three forces of 5g, 6g, and 12g in equilibrium.
Explanation:
Equilibrium means their sum must be zero.
Here the forces are 5g, 6g, and 12g.
For number of forces to be in equilibrium the magnitude of largest vector should be less than sum of the magnitude of other vectors.
Here
Magnitude of largest force = 12 g
Sum of magnitudes of other forces = 5g + 6g = 11g
Magnitude of largest force > Sum of magnitudes of other forces
So this forces cannot form equilibrium.
We cannot place three forces of 5g, 6g, and 12g in equilibrium.
Answer:
a=0.555m/s^2
Explanation:
First we find the distance traveled from the moment the engineer reacts to the car, assuming uniform movement
X=VT
X=(18)(0.45)=8.1m
then we find the distance at which the deceleration begins, which is obtained by subtracting the total distance with the inner result
X=300-8.1=291.9
finally we use the equation for constant acceleration
Vf=0 final speed
Vo=18m/s= initial speed
X=291.9m
(Vf^2-Vo^2)/2X=a
(0-18^2)/(2*291.9)=a
a=0.555m/s^2
The appropriate description is ...
<span>b. the same amount of charge per second delivered to the resistor must return to the battery terminal</span>
The answer is a) because otherwise the forces can't be added as the objects will be different.
