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Elodia [21]
3 years ago
11

Flowchart symbols

Physics
1 answer:
MArishka [77]3 years ago
5 0

Answer:

Option (A)

Explanation:

A flowchart can be described as a representation of a process or an algorithm in a sequential manner (stepwise) in the form of diagrams. These steps are made of symbols that are connected to one another with the help of arrows. These arrows are used to show the direction of the process.  

There are mainly four symbols that are used to describe a flow chart, which includes-

  • Oval or Pill Shape- This type of symbol is used to depict the start or the end of a process.
  • Rectangle Shape- This type of symbols is used to describe the process .
  • Diamond Shape- This type of symbol is used to represent decision s.
  • Parallelogram- This type of symbol is used for the representation of an input or an output.

Thus, the correct answer is option (A).

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Clasifica los siguientes enunciados de acuerdo a si se describen movimientos
Alenkasestr [34]

Answer:

- translation

- rotation, traslation

- traslation, rotation

- vibrating

Explanation:

El movimiento de un cuerpo cae por su propio peso <u>traslación</u>.

El movimiento de las ruedas de una bicicleta al ser pedaleada <u>rotación, traslación</u>.

El movimiento de la Tierra alrededor de sol <u>traslación, rotación</u>.

El movimiento de la cuerda de una guitarra cuando se está tocando música <u>vibración</u>.​

- - - - - - - - - - - - - - - - - - - -  - - - - - - - -  

The movement of a body falls under its own  weight <u>translation</u>.

The movement of the wheels of a bicycle when being pedaled <u>rotation, translation.</u>

The movement of the Earth around the sun, <u>translation, rotation</u>.

The movement of a guitar string when playing  music <u>vibrating</u>.

7 0
3 years ago
Tom kicks a soccer ball on a flat, level field giving it an initial speed of 20 m/s at an angle of 35 degrees above the horizont
SVEN [57.7K]

Answer:

(a) 2.34 s

(b) 6.71 m

(c) 38.35 m

(d) 20 m/s

Explanation:

u = 20 m/s, theta = 35 degree

(a) The formula for the time of flight is given by

T = \frac{2 u Sin\theta }{g}

T = \frac{2 \times 20 \times Sin35 }{9.8}

T = 2.34 second

(b) The formula for the maximum height is given by

H = \frac{u^{2} \times Sin^{2}\theta }{2g}

H = \frac{20^{2} \times Sin^{2}35 }{2 \times 9.8}

H  = 6.71 m

(c) The formula for the range is given by

R = \frac{u^{2} \times Sin 2\theta }{g}

R = \frac{20^{2} \times Sin 2 \times 35}{9.8}

R = 38.35 m

(d) It hits with the same speed at the initial speed.

8 0
3 years ago
The diagram shows waves of sound travelling through the air. By which factor is the sound intensity decreased at 3 meters?
SIZIF [17.4K]
The diagram is missing; however, we know that the intensity of a sound wave is inversely proportional to the square of the distance from the source:
I(r)= \frac{1}{r^2}
where I is the intensity and r is the distance from the source.

We can assume for instance that the initial distance from the source is r=1 m, so that we put 
I= \frac{1}{r^2}= \frac{1}{(1)^2}=1
The intensity at r=3 m will be
I= \frac{1}{r^2}= \frac{1}{(3)^2}= \frac{1}{9}
Therefore, the sound intensity has decreased by a factor 1/9.
8 0
3 years ago
Read 2 more answers
A pirate ship shoots a cannon towards an oncoming ship. The cannon ball has a mass of 25 kg and the ship has a mass of 2500 kg.
mars1129 [50]

Answer:

25 m/s in the opposite direction with the ship recoil velocity.

Explanation:

Assume the ship recoil velocity and velocity of the cannon ball aligns. By the law of momentum conservation, the momentum is conserved before and after the shooting. Before the shooting, the total momentum is 0 due to system is at rest. Therefore, the total momentum after the shooting must also be 0:

m_sv_s + m_bv_b = 0

where m_s = 2500 kg, m_b = 25 kg are masses of the ship and ball respectively. v_s = 0.25 m/s, v_b are the velocities of the ship and ball respectively, after the shooting.

2500*0.25 + 25*v_b = 0

25v_b = -2500*0.25

v_b = -2500*0.25/25 = -25 m/s

So the cannon ball has a velocity of 25 m/s in the opposite direction with the ship recoil velocity.

3 0
3 years ago
A 12000 kg boat is moving 4.25 m/s. Its engine pushes 9200 N forward, but the current pushes back at 12,500 N. How much times do
Verizon [17]

Answer:

15.5 seconds

Explanation:

Apply Newton's second law:

∑F = ma

-12500 + 9200 = (12000) a

a = -0.275 m/s²

v = at + v₀

0 = (-0.275) t + 4.25

t = 15.5 s

It takes the boat 15.5 seconds to stop.

7 0
3 years ago
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