Answer:
- translation
- rotation, traslation
- traslation, rotation
- vibrating
Explanation:
El movimiento de un cuerpo cae por su propio peso <u>traslación</u>.
El movimiento de las ruedas de una bicicleta al ser pedaleada <u>rotación, traslación</u>.
El movimiento de la Tierra alrededor de sol <u>traslación, rotación</u>.
El movimiento de la cuerda de una guitarra cuando se está tocando música <u>vibración</u>.
- - - - - - - - - - - - - - - - - - - - - - - - - - - -
The movement of a body falls under its own weight <u>translation</u>.
The movement of the wheels of a bicycle when being pedaled <u>rotation, translation.</u>
The movement of the Earth around the sun, <u>translation, rotation</u>.
The movement of a guitar string when playing music <u>vibrating</u>.
Answer:
(a) 2.34 s
(b) 6.71 m
(c) 38.35 m
(d) 20 m/s
Explanation:
u = 20 m/s, theta = 35 degree
(a) The formula for the time of flight is given by


T = 2.34 second
(b) The formula for the maximum height is given by


H = 6.71 m
(c) The formula for the range is given by


R = 38.35 m
(d) It hits with the same speed at the initial speed.
The diagram is missing; however, we know that the intensity of a sound wave is inversely proportional to the square of the distance from the source:

where I is the intensity and r is the distance from the source.
We can assume for instance that the initial distance from the source is r=1 m, so that we put

The intensity at r=3 m will be

Therefore, the sound intensity has decreased by a factor

.
Answer:
25 m/s in the opposite direction with the ship recoil velocity.
Explanation:
Assume the ship recoil velocity and velocity of the cannon ball aligns. By the law of momentum conservation, the momentum is conserved before and after the shooting. Before the shooting, the total momentum is 0 due to system is at rest. Therefore, the total momentum after the shooting must also be 0:

where
are masses of the ship and ball respectively.
are the velocities of the ship and ball respectively, after the shooting.



So the cannon ball has a velocity of 25 m/s in the opposite direction with the ship recoil velocity.
Answer:
15.5 seconds
Explanation:
Apply Newton's second law:
∑F = ma
-12500 + 9200 = (12000) a
a = -0.275 m/s²
v = at + v₀
0 = (-0.275) t + 4.25
t = 15.5 s
It takes the boat 15.5 seconds to stop.