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Lyrx [107]
3 years ago
6

What would be the indication if there is a high frequency and pitch?

Physics
1 answer:
il63 [147K]3 years ago
6 0
Higher pitched sounds produce waves which are closer together than for lower pitched sounds. A smaller triangle or cymbal will make a relatively higher pitch note
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The position of an electron is given by , with t in seconds and in meters. At t = 3.99 s, what are (a) the x-component, (b) the
egoroff_w [7]

Answer:

A. Vx = 3.63 m/s

B. Vy = -45.73 m/s

C. |V| = 45.87 m/s

D. θ = -85.46°

Explanation:

Given that position, r, is given as:

r = 3.63tˆi − 5.73t^2ˆj + 8.16ˆk

Velocity is the derivative of position, r:

V = dr/dt = 3.63 - 11.46t^j

A. x component of velocity, Vx = 3.63 m/s

B. y component of velocity, Vy = -11.46t

t = 3.99 secs,

Vy = - 11.46 * 3.99 = -45.73 m/s

C. Magnitude of velocity, |V| = √[(-45.73)² + 3.63²]

|V| = √(2091.2329 + 13.1769)

|V| = √(2104.4098)

|V| = 45.87 m/s

D. Angle of the velocity relative to the x axis, θ is given as:

tanθ = Vy/Vx

tanθ = -45.73/3.63

tanθ = -12.6

θ = -85.46°

7 0
3 years ago
Which of the following equations can be used to directly calculate an object's impulse?
Iteru [2.4K]
I believe the answer is B
7 0
3 years ago
John enjoys watching crime shows and his best subject in school was chemistry. What might be a good career for him to explore? I
Vera_Pavlovna [14]
The answer is D forensic investigator
4 0
2 years ago
Read 2 more answers
PLEASE HELPPPPPPP!!!!!!!!!!
natka813 [3]

Answer:

F' = 800 N

Explanation:

The electrical force between charges is 400 N.

The electrical force between two charges is given by :

F=k\dfrac{q_1q_2}{r^2}

If q₁' = 2q₁, new force becomes,

F'=k\dfrac{q_1'q_2'}{r^2}\\\\F'=k\dfrac{2q_1\times q_2}{r^2}\\\\F'=2\times F\\\\F'=2\times 400\\\\F'=800\ N

So, the new force becomes 800 N.

8 0
3 years ago
Fill in the term that best completes the statement.<br> Work transfers<br> between objects.
Otrada [13]

Answer:

<em><u>Energy is the term that best completes the statement.</u></em>

<em><u></u></em>

<em><u>Hope this helps!</u></em>

3 0
3 years ago
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