I would solve the first equation for x and then sub that value into x in the second equation. That's the easiest way. x - 2y = 3 solved for x is x = 2y+3. Now sub that in for x in the second equation: 5(2y+3)+3y=2 and 10y + 15 + 3y = 2. 13y = -13, and y = -1. Now sub that y value into either equation to solve for x: x = 2(-1) + 3 gives us an x value of x = 1. Therefore, your solution to this system is (1, -1), first choice above.
So k in the first problem would =1/2
and i guess in the second problem just put k in place of the first space and in the second space put 8 for x. y would then =4. Idk if I did this right, though, I'm honestly a little confused too.
Answer:
5 hamburger packages and 6 bun packages
Step-by-step explanation:
It is asking for the highest common multiple of 12 and 10. the first time a multiple of 12 is divisible by 10 is at 12x5, which is 60. now divide 60 by 12 and 10, 5 and 6.
