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Licemer1 [7]
2 years ago
5

Enter a linear equation that models the situation.

Mathematics
2 answers:
LenKa [72]2 years ago
6 0
Answer : 1.30 + 3 then subtract that answer from 35
balu736 [363]2 years ago
3 0

Answer: 1.30p + 3n = 35

Step-by-step explanation:

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Solve each system by substitution.<br> -<br> y = 6x – 11<br> -2x – 3y=-7
densk [106]

Answer:

Point form (2.1)

Equation form: x=2,y=1

5 0
2 years ago
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Solve equation by using the quadratic formula.
Sati [7]

Answer: 1:  x=3, x=1

2:  x= -5

3:  There are 2 real solutions.

4:  There are 2 real solutions.

5:  There are no real solutions.

6.  There is 1 real solution.

7.  

8.  x= -6, x = -2

9.  x = -1/6, x=1

10.  

Explanation:

1.  The quadratic formula is

Substituting our known information we have:

2.  Rewriting the quadratic in standard form we have x²+10x-25=0. Substituting this into the quadratic formula gives us:

3.  The discriminant is b²-4ac.  For this problem, that is 20²-4(-4)(25)=400--400=800.  Since this is greater than 0, there are 2 real solutions.

4.  The discriminant in this problem is 7²-4(2)(-15)=49--120=49+120=169.  This is greater than 0, so there are 2 real solutions.

5.  The discriminant in this problem is 1²-4(-2)(-28)=1-224=-223.  Since this is less than 0, there are no real solutions.

6.  If the discriminant of a quadratic is 0, then by definition there is 1 real solution.

7.  Rewriting the quadratic we have 3x²-4x-2=0.  Using the quadratic formula we have:

8.  Factoring this trinomial we want factors of 12 that sum to 8.  6*2 = 12 and 6+2=8, so those are our factors.  This gives us:

(x+6)(x+2)=0

Using the zero product property we know that either x+6=0 or x+2=0.  Solving these equations we get x= -6 or x= -2.

9.  Factoring this trinomial we want factors of 6(-1)=-6 that sum to -5.  (-6)(1)=-6 and -6+1=-5, so this is how we "split up" the x term:

6x²-6x+1x-1=0

We group together the first two and the last two terms:

(6x²-6x)+(1x-1)=0

Factor the GCF out of each group.  In the first group, that is 6x:

6x(x-1)+(1x-1)=0

In the second group, the GCF is 1:

6x(x-1)+1(x-1)=0

Both terms have a factor of (x-1), so we can factor it out:

(x-1)(6x+1)=0

Using the zero product property, we know either x-1=0 or 6x+1=0.  Solving these equations we get x=1 or x=-1/6.

10.  Substituting our information into the quadratic formula we get:

Step-by-step explanation:

5 0
2 years ago
Solve for n
malfutka [58]
<span>(5 2/3+8 1/4)+9 3/4=n+18
</span><span>5 2/3+8 1/4+9 3/4=n+18
</span>5 2/3 + 18 = n + 18          | - 18
5 2/3 = n
7 0
2 years ago
Read 2 more answers
if a right triangle has one side measuring 3√2 and another side measuring 2√3, what is the length of the hypotenuse?
lina2011 [118]

Answer:

<h2>\sqrt{30}</h2>

Step-by-step explanation:

Given,

Perpendicular ( p ) = 3√2

Base ( b ) = 2√3

Hypotenuse ( h ) = ?

Now, let's find the length of the hypotenuse:

Using Pythagoras theorem:

{h}^{2}  =  {p}^{2}  +  {b}^{2}

plug the values

{h}^{2}  =  {(3 \sqrt{2} )}^{2}  +  {(2 \sqrt{3} )}^{2}

To raise a product to a power, raise each factor to that power

{h}^{2}  = 9 \times 2 + 4 \times 3

Multiply the numbers

{h}^{2}  = 18 + 12

Add the numbers

{h }^{2}  = 30

Take the square root of both sides of the equation

h =  \sqrt{30}

Hope this helps...

Best regards!!

6 0
3 years ago
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Find the slope of the line that passes through (-2, 8) and (-10, 14)
vesna_86 [32]
Hello!

To find the slope we divide the difference of the y-values by the difference of the x-values as shown below.

\frac{14-8}{-10+2} = -\frac{6}{8} = -\frac{3}{4}

The slope of our line is -3/4.

I hope this helps!
8 0
3 years ago
Read 2 more answers
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