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LenKa [72]
3 years ago
10

Two harmonic sound waves reach an overseveer simulatenouslt. the obsever hears the sound intensity rise and fall with a time of

0.2 between the maximmu intensity and the successing minimum intensity. What is the difference in frequency of the two sound waves?
Physics
1 answer:
irakobra [83]3 years ago
4 0

Answer:

dF=2.5Hz

Explanation:

From the question we are told that:

Time T=0.2sec

Generally the Period is given as

 T= 2 * 0.2 = 0.4

Therefore difference in frequency dF

 dF=\frac{1}{T}

 dF=\frac{1}{0.4}

 dF=2.5Hz

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Answer:

Distancia, S = 136 metros

Explanation:

Dados los siguientes datos;

Aceleración, a = 3 m/s²

Velocidad inicial, u = 5 m/s

Tiempo, t = 8 segundos

Para encontrar la distancia recorrida, usaríamos la segunda ecuación de movimiento;

S = ut + ½at² Sustituyendo en la fórmula, tenemos;

S = 5 × 8 + ½ × 3 × 8²

S = 40 + 1,5 × 64

S = 40 + 96

Distancia, S = 136 metros

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\boxed {\boxed {\sf True}}

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Butbot na dili na tinuod ga timala ra ko ana
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