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alexgriva [62]
3 years ago
14

In a hydrogen atom, the electron in orbit around the proton feels an attractive force of about 7.45 × 10−8 N. If the radius of t

he orbit is 5.89 × 10−11 m, what is the frequency? Answer in units of rev/s
Physics
1 answer:
Tcecarenko [31]3 years ago
8 0
The attraction force provides the electron's centripetal force. 

<span>8.30^-8N = mrω² </span>

<span>ω² = 8.30^-8 / (9.11^-31 kg x 4.70^-11m) .. .. ω² = 1.94^33 (rad/s)² .. .. ω = 4.40^16 rad/s </span>

<span>f = ω/2π = 4.40^16 / 2π .. .. .. ►f = 7.0^15 Hz</span>
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Llana [10]

Answer: 0.1 m/s

Explanation:

Use formula,

v = f * w where, v is speed, f is frequency and w is wavelength.

Now,

v = 2 * 5 * 10 ^ -2 ( Remember to convert all the units to SI units. Here 5 cm becomes 5 * 10 ^ -2 m. )

v = 0.1 m/s.

8 0
3 years ago
A lemon with mass 0.3 kg falls out of a tree from a height of 1.8 m. How much mechanical energy does the lemon have just before
Zina [86]
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3 0
3 years ago
Read 2 more answers
What does Newton's 2nd Law explain?
kow [346]

Answer:

C. Why you must push harder to move a car farther.

Explanation:

Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.

Mathematically, it is given by the formula;

Acceleration = \frac {Force}{mass}

Hence, Newton's 2nd Law explains why you must push harder to move a car farther because of its mass. Thus, it is important to increase the force that the engine provides and decrease the mass of the car.

6 0
2 years ago
Given: G = 6.672 × 10−11 N · m2 /kg2 Io, a satellite of Jupiter, has an orbital period of 1.24 days and an orbital radius of 4.1
Dahasolnce [82]

Answer:

Mass of Jupiter = 4.173×10^15kg

Explanation:

Using Kepler's 3rd law, it states that the orbital period T is related to the distance,r as:

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r = radius

M = masd of jupiter

Rearranging the formular to make M the subject of formular

T^2 × 4 pi = G M × r^3

(T^2 × 4 pi) / (G× r^3) = M

(1.24^2 × 4 × 3.142) /(6.672×10^-11)(4.11×10^8)^3

M = 19.32 /6.672×10^-11)(4.11×10^8)^3

M = 19.32 / 4.63 ×10^15

M = 4.173×10^15kg

6 0
2 years ago
If an exit sign is hanging from the ceiling by three chains each of which has a tension of 15N what is the weight of the sign
kvasek [131]
The weight is 45 N, because the three chains hold the sign, and each contributes 15 N.

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3 0
3 years ago
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