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3 years ago

Determine the solution for the equation.

Mathematics

1 answer:

Ilya [14]3 years ago

6 0

Answer:
2^4=16
Hope i helped

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Is 32.725 greater or less than 32.735

AURORKA [14]

’32.725 is less than. 32.735

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3 years ago

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What is the x and y intercept of -1/2x+3?

slavikrds [6]

Answer:

-1/2x+3=y

to find xint make y=0

-1/2x+3=0

-1/2×=-3

x=6

so xint=6

to find yint make x=0

-1/2(0)+3=y

y=3

yint=3

3 0

3 years ago

3−4x−10=−7−4x I need full steps 1 by 1

Len [333]

Answer:

x € R

Step-by-step explanation:

3 − 4x − 10 = −7 − 4x

-4x + 4x = -7 - 3 + 10

0 = 0

x € R

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3 years ago

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Simplify the following expression 5-⁵/2 x 5⁹/2

yarga [219]

Given:

Consider the given expression is

$5^{-\frac{5}{2}}\times 5^{\frac{9}{2}}$

To find:

The simplified form of the given expression.

Solution:

We have,

$5^{-\frac{5}{2}}\times 5^{\frac{9}{2}}$

Using properties of exponents, we get

$=5^{-\frac{5}{2}+\frac{9}{2}}$ $[\because a^ma^n=a^{m+n}]$

$=5^{\frac{-5+9}{2}}$

$=5^{\frac{4}{2}}$

$=5^{2}$

$=25$

Therefore, the simplified form of given expression is 25.

7 0

3 years ago

1. What is the slope of a line that is parallel to the line represented by the equation y=-2/5x + 4/5

lbvjy [14]

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to find the slope of the line that is parallel to the line $\star~\mathrm{y=-\cfrac{2}{5}x+\cfrac{4}{5}}$ .

$\triangle~\fbox{\bf{KEY:}}$

Parallel lines have the same slope.

So let's first determine the slope of the first line, and then let's find the slope of the line that's parallel to it.

$\circ\!\!\!\star\mathcal{HINT:}$

The slope is the coefficient of x.

So the slope is

$\star~\mathrm{-\cfrac{2}{5}}$ .

Can you guess the slope of the line that is parallel to the first line?

That's right! The slope is...

$\star~\mathrm{-\cfrac{2}{5}}$

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

4 0

2 years ago