First, you should convert the temperature unit to absolute temperature.
Second, you shoul graph the points. Then you will find a pretty linear correlations among the points.
You can pick between using the best fit line or you could observe that as you get to higher temperatures the linear behavior is "more perfect".
I found this best fit line:
P = 2.608T + 14
Then, for T = 423K
P = 2.608(423) + 14 = 1117 mmHg
If you prefer to use the last two points, this is the calculus:
[P - P1] / [T - T1] = [P2 - P1] / [T2 - T1]
[P - 960]/[423 -373] = [960 - 880] / [373- 343]
=> P = 1093.3 mmHg.
You can pick any of the results 1177 mmHg or 1093 mmHg, You need more insight to choose one of them: conditions and error of the experiment for example.
Hey there!:
Molar mass CuSO4*5H2O = 249.68 g/mol
Therefore:
1 mole CuSO4*5H2O ---------------- 249.68 g
3.2 moles --------------------------------- ?? ( mass of CuSO4*5H2O )
mass CuSO4*5H2O = 249.68 * 3.2
mass CuSO4*5H2O = 798.97 g
Hope that helps!
Im pretty sure it would be a total of 13
Answer: 36.6°C
Explanation:
Given that,
initial pressure of helium (P1) = 1.20 atm
Initial temperature (T1) = 22.0°C
Final temperature (T2) = ?
Final pressure of helium (P2) = 2.00 atm
Since pressure and temperature are given while volume is constant, apply the formula for pressure's law
P1/T1= P2/T2
1.20 atm / 22.0°C = 2.00 atm / T2
Cross multiply
1.20 atm•T2= 2.00 atm•22°C
1.20 atm•T2= 44 atm•°C
Divide both sides by 1.20 atm
1.20 atm•T2/1.20 atm = 44 atm•°C/1.20 atm
T2 = 36.6°C