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AlexFokin [52]
3 years ago
6

Answer my questions plz help

Mathematics
1 answer:
coldgirl [10]3 years ago
3 0

9514 1404 393

Answer:

  • a = -2/3, b = 8, c = -24
  • y-intercept: (0, -24)
  • x = -b/(2a) = -8/(2(-2/3)) = 8(4/3)
  • x = 6
  • DOWN
  • Max: (6, 0)
  • Vertex: (6, 0)
  • Domain: {x | x ∈ ℝ}
  • Range: {x | x ≤ 0}

Step-by-step explanation:

To find a, b, c, compare the given function to ...

  f(x) = ax² +bx +c

You will see that ...

  • a = -2/3
  • b = 8
  • c = -24

The y-intercept is the function value for x=0. It is the constant term:

  y-intercept = f(0) = -24

Use the above values of a, b to find the line of symmetry.

  x = \dfrac{-b}{2a}=\dfrac{-8}{2\cdot\dfrac{-2}{3}}=8\cdot\dfrac{3}{4}=6

Per the calculation, the line of symmetry is ...

  x = 6

The negative leading coefficient tells you the parabola opens DOWN.

Because it opens down, the vertex at (6, 0) is a Maximum.

As with any polynomial, the domain is "all real numbers", hence any x that is an element of Reals.

The range is all values below the vertex (including the vertex), so is ...

  x ≤ 0

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PLZ HELP/......<br> :)<br><br> :?
alexdok [17]

Answer:

3 gallons of diesel weight = <u>22.2 pounds </u>

The constant of variation = <u>7.4</u>

The quantities vary <u>directly</u>

Step-by-step explanation:

Given:

5 gallons of gas weights = 37 pounds

To find

a) the weight of 3 gallons of gas.

b) if the quantities vary directly or inversely.

c) the constant of variation.

Solution:

Applying unitary method to find weight of 3 gallons of gas.

If 5 gallons weight = 37 pounds

Then, 1 gallon will weight = \frac{37}{5} =7.4 pounds

Thus, 3 gallons will weight = 3\times 7.4 = 22.2 pounds

Listing out the data we have:

1 gallon = 7.4 pounds

3 gallons = 22.2 pounds

5 gallons = 37 pounds

From the data, we find out that as the number of gallons of gas increases the weight of gas also increases. This shows that these quantities are directly proportional to each other.

<em>The unit rate of the quantities is called the constant of variation.</em>

<em>Unit rate: 7.4 pounds per gallon</em>

Thus, the constant of variation = 7.4

8 0
3 years ago
A train traveled 3/5 of the distance between two cities in 1/4 of an hour. At this rate, what fraction of the distance between t
Mkey [24]

Answer: 2 2/5 distance

Step-by-step explanation:

You know 1/4 of an hour you travel of 3/5 of distance, so let’s set an proportion: 1/4 hr = 3/5 of distance, multiply 4 on both sides, and you get 2 2/5 distance. Hope this helps!

4 0
4 years ago
The data below gives the number of speeding tickets given per day at a certain location on a highway over a two-week period.
kramer
Do you have the rest of the answers ? 

6 0
3 years ago
the odds in favor of frank mckinnis winning a hot dog eating contest are 2:9the odds in favor of frank mckinnis winning a hot do
Ivahew [28]

Answer:

Consider the complete question is,

'The odds in favor of frank McKinney winning a hot dog eating contest are 2:9,

  • Determine the probability that Frank will win the contest,
  • Determine the probability that Frank will not win the contest'

Solution :

We know that,

Odds in favor : the ratio of the number of ways that an outcome can occur compared to how many ways it cannot occur.

We have,

\frac{\text{Number of ways of winning the contest}}{\text{Number of ways of not wining the contest}}=\frac{2}{9}

So, total outcomes = 2 + 9 = 11,

\text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}

Thus, the probability that Frank will win the contest = \frac{2}{11}

And,

The probability that Frank will win the contest = \frac{9}{11}

5 0
4 years ago
Read 2 more answers
Differentiate y = 8x/ 3 − tan(x)
vagabundo [1.1K]

Answer:

\frac{dy}{dx}=\frac{8(xsec^2(x)-tan(x)+3)}{(3-tan(x))^2}

Step-by-step explanation:

y=\frac{8x}{3-tan(x)}\\ \\\frac{dy}{dx}=\frac{(3-tan(x))(\frac{d}{dx}8x)-(\frac{d}{dx}(3-tan(x)))(8x)}{(3-tan(x))^2}\\ \\ \frac{dy}{dx}=\frac{(3-tan(x))(8)-(-sec^2(x))(8x)}{(3-tan(x))^2}\\ \\ \frac{dy}{dx}=\frac{24-8tan(x)+8xsec^2(x)}{(3-tan(x))^2}\\ \\ \frac{dy}{dx}=\frac{8xsec^2(x)-8tan(x)+24}{(3-tan(x))^2}\\\\ \frac{dy}{dx}=\frac{8(xsec^2(x)-tan(x)+3)}{(3-tan(x))^2}

Remember to use the Quotient Rule

4 0
2 years ago
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