This is a simple problem based on combinatorics which can be easily tackled by using inclusion-exclusion principle.
We are asked to find number of positive integers less than 1,000,000 that are not divisible by 6 or 4.
let n be the number of positive integers.
∴ 1≤n≤999,999
Let c₁ be the set of numbers divisible by 6 and c₂ be the set of numbers divisible by 4.
Let N(c₁) be the number of elements in set c₁ and N(c₂) be the number of elements in set c₂.
∴N(c₁) =

N(c₂) =

∴N(c₁c₂) =

∴ Number of positive integers that are not divisible by 4 or 6,
N(c₁`c₂`) = 999,999 - (166666+250000) + 41667 = 625000
Therefore, 625000 integers are not divisible by 6 or 4
Answer:
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Answer:
x<25
Step-by-step explanation:
Let's solve your inequality step-by-step.
2.4x−9<1.8x+6
Step 1: Subtract 1.8x from both sides.
2.4x−9−1.8x<1.8x+6−1.8x
0.6x−9<6
Step 2: Add 9 to both sides.
0.6x−9+9<6+9
0.6x<15
Step 3: Divide both sides by 0.6
0.6x/0.6 < 15/0.6
x<25
Please, do not post more than 1 or 2 questions at a time. Out of courtesy I will address one of your six questions here:
<span>2x + 4 = 3(x – 2) + 1
You are to solve this for x.
1) perform the multiplication: </span><span>2x + 4 = 3x - 6 + 1
2) combine like terms: 4+6-1 = x
3) solve for x: x = 11
4) check: Is 2(11) + 4 = 3(11-2) + 1 true?
Is 22+4 = 33-6 true? NO. Try again, looking for the mistake:
</span><span>2x + 4 = 3(x – 2) + 1 => 2x + 4 = 3x - 6 + 1
4 = x - 5
9 = x
Check: Is 2(9) + 4 = 3(9-2) + 1 true? Is 18+4 = 22 true? YES.
The solution to #1 is x = 9 (answer).
Submit your other questions separately, please.
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Answer:
it will take her 2 hours and 45 minutes