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3 years ago

What is the fifth term of the geometric sequence whose first three terms are 486, 162, and 54?

Mathematics

1 answer:

Scorpion4ik [409]3 years ago

3 0

Answer:

Step-by-step explanation:

an = ar^(n-1)

a = first term

n = nth term

r = common ratio

r = r2 / r1 = r3 / r2

The first 3 terms are :

486, 162, and 54

Hence,

a = 486

r = 162 / 486 = 1/3

Hence ;

a5 = 486(1/3)^5 - 1

a5 = 486(1/3)^4

a5 = 486(1 / 81)

a5 = 486 * 1 / 81

a5 = 486 / 81

a5 = 6

The 5th term of the geometric progression will be ; 6

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Part 1) $30\ coupons$

Part 2) $12\ sandwiches$

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