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statuscvo [17]
2 years ago
9

I will mark brainiest is my answer is correct?

Mathematics
1 answer:
Alex Ar [27]2 years ago
5 0
Your answer is correct
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4^2-6(2^x)-16=0<br><br><br>solve for x
ahrayia [7]
Assuming that   <span>4^2-6(2^x)-16=0   is correct, we can rearrange it as:

</span><span>-6(2^x) + 4^2 - 16=0

Are you sure it's not   </span>6(2^x) + 4^2 - 16=0  ?

If   6(2^x) + 4^2 - 16=0    is correct, then

6(2^x) + 4^2 - 16=16 - 16 = 0, that is,   6(2^x) = 0.  Then x = 0 (answer)
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