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3 years ago

14

X^2-11=53 in the simplest form

1 answer:

Vedmedyk [2.9K]3 years ago

3 0

Answer:

x=±8

Step-by-step explanation:

You add 11 on both sides

x^2=53+11

x^2 = 64 so

x=8 or x=-8

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Consider the following sets:

bagirrra123 [75]

U = {points on the coordinate plane}
A = {solutions to the equation y = 2x + 5}
B = {points on the line y = mx}

Value of the slope m so that {2x + 5} ∩ {mx} =Ф
This means that {2x + 5} never intersects with {mx}
To that end m=2 (same slope), if so the 2 linear functions:

y = 2x+5 and y = 2x are PARALLEL

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3 years ago

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Which equation shows y-5=x converted to slope intercept form.

andreyandreev [35.5K]

Answer:

C) y = x + 5

Step-by-step explanation

Add 5 to both sides

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3 years ago

What’s 1/5 divided by 1/12?

Ksivusya [100]

When divided fractions you flip the second fraction

1/5 x 12/1

This then equals
12/5

That simplifies to 2 2/5

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3 years ago

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The width of a rectangle field is 3h yards and its length is 3 yards longer than the width. The field has a fence around its per

d1i1m1o1n [39]

Answer:

Part a) $P=(12h+2)\ yd$

Part b) The expression that represent the cost of fencing the field is $(336h+56)$

Part c) $\$1,736$

Step-by-step explanation:

<u>The complete question in the attached figure</u>

Part a) we know that

The perimeter of the rectangular field (excluding the width of the gate) is equal to

$P=2(L+W)-4$

we have

$L=(3h+3)\ yd\\W=3h\ yd$

substitute the given values

$P=2(3h+3+3h)-4$

$P=2(6h+3)-4\\P=12h+6-4\\P=(12h+2)\ yd$

Part b) we know that

To find out the cost of fencing the field (excluding the gate) , multiply the perimeter by the cost of $28 per yard

so

$28(12h+2)=336h+56$

Part c) we have

h=5

substitute the value of h in the expression of the cost

$336(5)+56=\$1,736$

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4 years ago

If f(x) = 3x - 2 and g(x) = 2x+1, find (f+ g)(x).<br><br> A. 5x-1<br> B. X-3<br> c. 5x-3<br> D. X-1

Vladimir79 [104]

Answer:

A. 5x - 1

Step-by-step explanation:

3x - 2

+ 2x + 1

------------

5x-1

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3 years ago

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