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irina [24]
3 years ago
7

I need help with this

Mathematics
1 answer:
Nat2105 [25]3 years ago
4 0
You divide to get the answer
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Q6. A colony of ants is beg please help, I don’t know this and I have to hand it in in 20 mins
Savatey [412]

Answer:

a) The number of ants in week three is shown through the following geometric progression: 500*1.1*1.1*1.1

b) 1.21

Step-by-step explanation:

We know that 500 ants are increasing at a rate of 10% every week which means that we can calculate the week one ants like this

500*1.1

Week two

500*1.1*1.1

and so on.

We write the following equation

500(1.1)^n where n is the number of weeks

We plug in 8 and then 6 for n in the equation above and get

500(1.1)^8=1071.79

500(1.1)^6=885.78

Divide and get that p=1.21

7 0
3 years ago
I please need help with this question. Thank you
Diano4ka-milaya [45]

Part (A)

The input variable is the shoe size because it is along the horizontal axis, or x axis. It's not clear what the units for the shoe size are, but it's possible the units are in inches.

The output variable is the y value, which in this case is the height. The units for the height is in inches.

====================================================

Part (B)

We have a positive trend. We determine this visually by noting the regression line, or trend line, is going upward as we move from left to right.

Algebraically, the equation for the trend line has a positive slope, which leads to a positive trend.

A positive trend is where x and y increase together. As shoe size goes up, height goes up as well.

While not all the points are on the line, there is a tendency for the points to go uphill as we move from left to right.

As for the strength of the correlation, that part is subjective. If we knew the correlation coefficient r, then we could be more certain; however, we don't know this value. So instead we have to eyeball the given graph and give an estimate. Based on the graph, I'd say there's a moderate positive correlation going on. It's somewhere in the middle of weak and strong positive correlation because the data points are somewhat scattered randomly, but they trend upward nonetheless.

====================================================

Part (C)

The rate of change is the slope. The slope is the coefficient of the independent variable x. In this problem, the slope is 1.728

So the rate of change is 1.728 inches per shoe size.

In other words, as the shoe size increases by 1 unit (1 inch perhaps?), the height will increase by roughly 1.728 inches.

---------------------------------------------------------

Extra info:

The equation

Height = 51.46 + 1.728(Shoe Size)

is the same as

y = 51.46 + 1.728x

where x is the shoe size and y is the height

We can rearrange that into

y = 1.728x + 51.46

So that it matches with the familiar y = mx+b slope intercept form. This is optional.

3 0
3 years ago
Write the recursive rule and an explicit rule for the geometric sequence 9,27,81,243
SashulF [63]

Answer:

Recursive

a(1) = 9 ; a(n+1) = 3 * a(n)

Explicit

a(n) = 9 * 3^(n-1)


5 0
3 years ago
HURRY!!!!!! What is the equation of a line that passes through the point (8, −2) and is parallel to the line whose equation is 3
Ipatiy [6.2K]
4y= -3x+15

y= (-3/4)x+15/4

y+2= (-3/4)(x-8)

y+2= (-3/4)x+6

y= (-3/4)x+4
7 0
3 years ago
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0
2 years ago
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