The answer to your question is true
IT'S stigma as the stigma is the female part of the flower. it has a tube leading down to the ovules and they fertilize
Answer:
Let ‘Xᶜ’ be the recessive allele for colour blindness and ‘X’ be the normal (dominant) allele.
Since Abby's father was colour blind, Abby must be a carrier for the same.
Which means Abby's genotype would be ‘XXᶜ’.
Now, Ryan is not colourblind which means his genotype would be ‘XY’.
Now, talking about their daughter, she would inherit a normal ‘X’ from Ryan and either ‘X’ or ‘Xᶜ’ from Abby.
Which means she wouldn't be colourblind but she might be a carrier of the disorder.
XXᶜ × XY
⬇️ ⬇️
X, Xᶜ X
↘️ ↙️
XX , XXᶜ
Their daughter will have either XX genotype or XXᶜ genotype.
And her chances of being colourblind thus, becomes zero.
Answer:
3.14 residues
Explanation:
This kind of sheets has the particularity that the distance between adjacent residues is 3.5 Angstroms. Furthermore, there are two residues per cycle.
Hence, we can calculate easily the number of residues in a segment, by using the expression:
Nr = (256 Å) / (3.5 Å/residue) = 3.14 residues
I hope this is useful for you
Regards
