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3 years ago

04.01 mc y-2x=-1 and 2y-x=4 choose the correct graph of the given systems of equations

Mathematics

1 answer:

ira [324]3 years ago

6 0

Answer:

1st one m=0

y= 0.49875311x / cm

No horizonal asymptotes

x= 1/2 + 2.005 mcy

2nd one is

slope 1/2

y intercept (0,2)

x y

-4 0

0 2

Step-by-step explanation:

for 2

starting point ay y 2 make a point

then rise over run

go up 1 and to the right 2 and point , then up 1 and to the right 2 and point

there is your graph

You might be interested in

F(x) = 5x2 – 20x + 26 In vertex form

mihalych1998 [28]

Answer:

$f(x)=5(x-2)^{2}+6$

Step-by-step explanation:

we have

$f(x)=5x^{2} -20x+26$

This is the equation of a vertical parabola open upward

The vertex is a minimum

The equation of a vertical parabola in vertex form is equal to

$f(x)=a(x-h)^2+k$

where

(h,k) is the vertex

Convert the given function to vertex form

Factor the leading coefficient

$f(x)=5(x^{2} -4x)+26$

Complete the square

$f(x)=5(x^{2} -4x+4)+26-20$

$f(x)=5(x^{2} -4x+4)+6$

Rewrite as perfect squares

$f(x)=5(x-2)^{2}+6$ ------> equation in vertex form

The vertex is the point (2,6)

6 0

2 years ago

A study was recently conducted to estimate the mean cholesterol for adult males over the age of 55 years. From a random sample o

Komok [63]

Answer: Correct critical value = 2.2622

Step-by-step explanation:

Confidence interval for population mean when population standard deviation is unknown:

$\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}$ , where $\overline{x}$ = sample mean, n= sample size, s= sample standard deviation, $t_{\alpha/2}$ = two-tailed t value.

As per given: n= 10

degree of freedom : df = n-1=9

$\overline{x}=242.6\\\\s=73.33\\\\\alpha=5\%=0.05$

Critical t-value : $t_{\alpha/2,df}=t_{0.05/2,9}=t_{0.025,9}=2.2622$

So, the 95 percent confidence interval estimate for the mean :

$242.6\pm (2.2622)\dfrac{73.33}{\sqrt{10}}\\\\=242.6\pm (2.2622)(23.19)\\\\\approx242.6\pm52.46\\\\=(242.6-52.46,\ 242.6+52.46)\\\\=(190.14,\ 295.06)$