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lesantik [10]
2 years ago
9

Could anyone help answer the question in the photo?

Mathematics
1 answer:
Kipish [7]2 years ago
7 0

Answer:

n = -3/10

Step-by-step explanation:

Given the expression \frac{\sqrt[5]{b} }{\sqrt[]{b} }

\frac{\sqrt[5]{b} }{\sqrt[]{b} } \\= \frac{b^{1/5}}{b^{1/2}} \\= b^{1/5-1/2}\\= b ^{2-5/10}\\= b^{-3/10}\\Compare \ b^n \ with \  b^{-3/10}\\\\n = -3/10

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How do I graph this? In picture below<br> please include the graph
Savatey [412]

Answer:

See the attached figure.

Step-by-step explanation:

The given function is called piecewise function which is the function that can be in pieces, i.e: defined by multiple sub-functions.

f(x)=\left \{ {{2x} \ , \ x\geq3  \atop {-\frac{1}{3}x+7 \ , \ x\leq 3 }} \right.

So, need to graph 2x in the interval [3,∞)

And graph -(1/3) x + 7  in the interval (-∞,3]

We will find that f(3) at the function 2x will be equal f(3) at the function -(1/3) x + 7

Which mean the function is continuous.

The attached figure represents the graph of function, it was graphed using the tables on the graph.

3 0
3 years ago
Simplify <br>28y=12x+84<br>I don't know this
irina1246 [14]
Divide everything by 4 getting:
7y=3x+21
then get all of the variables on one side by subtracting 3x:
7y-3x=21
7 0
3 years ago
Help me please i don't know what to do
astra-53 [7]

Answer:

a. a = 1, b = -5, c = -14

b. a = 1, b = -6, c = 9

c. a = -1, b = -1, c = -3

d. a = 1, b = 0, c = -1

e. a = 1, b = 0, c = -3

Step-by-step explanation:

a. x-ints at 7 and -2

this means that our quadratic equation must factor to:

(x-7)(x+2) = 0

FOIL:

x^2 + 2x - 7x - 14 = 0

Simplify:

x^2 - 5x - 14 = 0

a = 1, b = -5, c = -14

b. one x-int at 3

this means that the equation will factor to:

(x-3)^2=0

FOIL:

x^2 - 3x - 3x +9 = 0

Simplify:

x^2 - 6x + 9 = 0

a = 1, b = -6, c = 9

c. no x-int and negative y must be less than 0

This means that our vertex must be below the x-axis and our parabola must point down

There are many equations for this, but one could be:

-x^2-x-3=0

a = -1, b = -1, c = -3

d. one positive x-int, one negative x-int

We can use any x-intercepts, so let's just use -1 and 1

The equation will factor to:

(x+1)(x-1)=0

This is a perfect square

FOIL:

x^2-1=0

a = 1, b = 0, c = -1

e. x-int at \sqrt{3} , -\sqrt{3}

our equation will factor to:

(x+\sqrt{3} )(x-\sqrt{3)} =0

This is also a perfect square

FOIL and you will get:

x^2 - 3 = 0

a = 1, b = 0, c = -3

4 0
1 year ago
Given PQ = y, RS = 4y - 15, QR = 2 +6, and PS = 4a - 6, solve for the<br> length of RS and QR.
Anna11 [10]

Answer:

Check pdf

Step-by-step explanation:

Download pdf
3 0
3 years ago
PLEASE ANSWER ASAP!!!! ILL MAKE YOU BRAINIEST!!!<br><br> What is the length of XY?
JulijaS [17]
Not sure, but i think it's 4
6 0
3 years ago
Read 2 more answers
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