3 years ago

Could anyone help answer the question in the photo?

Mathematics

1 answer:

Kipish [7]3 years ago

7 0

Answer:

$n = -3/10$

Step-by-step explanation:

Given the expression $\frac{\sqrt[5]{b} }{\sqrt[]{b} }$

$\frac{\sqrt[5]{b} }{\sqrt[]{b} } \\= \frac{b^{1/5}}{b^{1/2}} \\= b^{1/5-1/2}\\= b ^{2-5/10}\\= b^{-3/10}\\Compare \ b^n \ with \ b^{-3/10}\\\\n = -3/10$

You might be interested in

Which expression is equivalent to the expression below? p+p+p+p+p+p+q+q+q+q p+p+p+p+p+p+q+q+q+q

Likurg_2 [28]

I am not sure if this is the type of expression that the question is asking for, but it could be 12p + 8q :)

8 0

3 years ago

Read 2 more answers

Mr. Benito just purchased 24 paint sets and a few sketch books for his art class. The total bill wūs $241. The paint sets cost a

Levart [38]

Answer:

He bought 32 sketchbooks

Step-by-step explanation:

E equals 32

6 0

2 years ago

Read 2 more answers

Each day Julian gives his dog, Banjo, 3 liters of water and 500 grams of food. Julian wants to track the total amount of the foo

Masteriza [31]

Answer:

The correct answer would be option C.

Step-by-step explanation:

Since he gives the dog 3 liters of water and 500 grams of food a day we know that on the fifth day the dog will have gotten 15 liters of water and 2,500 grams of food.

4 0

4 years ago

Read 2 more answers

In ΔBCD, the measure of ∠D=90°, the measure of ∠C=83°, and DB= 1.3feet. What is the length of CD to the nearest tenth of a foot.

Lina20 [59]

Answer:

$CD\approx0.2$

Step-by-step explanation:

By the tangent ratio, $tanC=\frac{DB}{CD}$ . Substituting the given values into this equation gives us:

$tan83$ ° $= \frac{1.3}{CD}$

$CD*tan83$ ° $=1.3$ (Multiply both sides of the equation by $CD$ )

$CD=\frac{1.3}{tan83\textdegree}$ (Divide both sides of the equation by $tan83\textdegree$ )

$CD=0.15962\approx0.2$

Hope this helps!

3 0

3 years ago

Find the solutions <br> x^2=16x-28

ioda

Minus 16x both sides and add 28 to both sides
x^2-16x+28=0
factor
hmm, what 2 numbers multiply to 28 and add to -16
hmm
1 and 28? nope
2 and 14? yep
since middle term is negative and last tem is positive, both of the factors are negative

(x-14)(x-2)=0
set each to zero
x-14=0
x=14

x-2=0
x=2

x=2 and 14

7 0

3 years ago