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ki77a [65]
3 years ago
13

What is the surface area? 5 ft 5 ft 5 ft cube

Mathematics
2 answers:
Paul [167]3 years ago
8 0

Answer:

125

Step-by-step explanation:

Nata [24]3 years ago
7 0

Answer:

The surface area of the cube is 150 .

Step-by-step explanation:

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Jo had $5 more than Nate and together<br> they had $43. How much did Nate have?
Andru [333]

Answer:

Step-by-step explanation:

43-5

=$38

38/2=19

Nate has $19

hope this helps!

6 0
3 years ago
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I am confused on how to solve this using L'hopital's<br> lim→0 (5^x - 3^x)/x
kupik [55]

Answer:

Same here

Step-by-step explanation:

6 0
3 years ago
The percent frequency distributions of job satisfaction scores for a sample of information systems (IS) senior executives and mi
tiny-mole [99]

Corrected Question

a. Develop a probability distribution for the job satisfaction score of a senior executive.

b. Develop a probability distribution for the job satisfaction score of a middle manager.

c. What is the probability a senior executive will report a job satisfaction score of 4 or 5?

d. What is the probability a middle manager is very satisfied?

Answer:

(c)0.83

(d)0.28

Step-by-step explanation:

The percent frequency distributions of job satisfaction scores os give below:

\left|\begin{array}{c|c|c}$Job Satisfaction Score&$IS Senior Executives(\%)&$IS Middle Managers(\%)\\1&5&4\\2&9&10\\3&3&12\\4&42&46\\5&41&28\end{array}\right|

(a)Probability distribution for the job satisfaction score of a senior executive.

\left|\begin{array}{c|c}$Job Satisfaction Score&$Relative Frequency (f_1(x))\\------&------\\1&0.05\\2&0.09\\3&0.03\\4&0.42\\5&0.41\end{array}\right|

(b)Probability distribution for the job satisfaction score of a middle manager.

\left|\begin{array}{c|c}$Job Satisfaction Score&$Relative Frequency (f_2(x))\\1&0.04\\2&0.10\\3&0.12\\4&0.46\\5&0.28\end{array}\right|

(c)Probability a senior executive will report a job satisfaction score of 4 or 5

P(a senior executive will report a job satisfaction score of 4 or 5)

=f_1(4)+f_1(5)\\=0.42+0.41\\=0.83

(d)Probability a middle manager is very satisfied

The probability a middle manager is very satisfied

=f_2(5)\\=0.28

7 0
3 years ago
So me 3 ways you get to 100
In-s [12.5K]
10 x 10 = 100
 20 + 20 + 20 + 20 +20 = 100
4 x 25 = 100
5 0
3 years ago
(5x+2)(x2-3x+6)<br> How do I do this and what’s the answer
lesya692 [45]
You need to use pemdas i will give i the answer in a minute
3 0
3 years ago
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