Answer:
0.5372
Step-by-step explanation:
Given that the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average birth rate of 1.8 births per hour.
Let X be the no of births in the hospital per hour
X is Poisson
with mean = 1.8
the probability of observing at least two births in a given hour at the hospital
= 
the probability of observing at least two births in a given hour at the hospital = 0.5372
Step-by-step explanation:
5x=1-6
5x=-5
<h3> x=-1</h3>
-5(-1)-8y=2
5-8y=2
-8y =2-5
-8y=-3
<h3> y=3/8</h3>
Answer:
x = -2
TU = 4
UB = 2
Step-by-step explanation:
you can add x^2 with 4x+10 and equate it to 6:
x^2 + 4x + 10 = 6
x^2 + 4x + 4
then u can use the roots formula : x = (-b ± √ (b2 - 4ac) )/2a
so it'll be x = {-4±[√16 - 4(4)]}/2
x= -2
then u can substitute it and find TU and UB
TU= (-2)^2 = 4
UB= 4(-2)+10 = 2
Answer:
10!
Step-by-step explanation:
Because I ate chicken nuggets!
