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4 years ago

1.Under normal atmospheric pressure what temperature does:

Physics

2 answers:

Andrej [43]4 years ago

6 0

Answer:

1.i)heat

ii.)heat

2.a.)b,c,d,a

b.)a.chlorination

Dimas [21]4 years ago

3 0

Answer:

Explanation:

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A 23 kg suitcase is being pulled with a constant speed by a handle that is at an angle of 29° above the horizontal. If the norma

Zina [86]

<u>Answer:</u>

The force F applied to the handle = 330.03 N

<u>Explanation:</u>

The force can be resolved in to two, horizontal component and vertical component. If θ is the angle between horizontal and applied force we have

Horizontal component of force = F cos θ

Vertical component of force = F sin θ

In this problem normal force exerted on the suitcase is 160 N, that is vertical component of force = 160 N and angle θ = 29⁰.

So, F sin 29 = 160

F = 330.03 N

The force F applied to the handle = 330.03 N

6 0

3 years ago

Read 2 more answers

At any point P, the total electric field due to a group of point charges equals the vector sum of the electric fields of the ind

wel

The answer is
A. True

8 0

3 years ago

I will give brainiest to the first person that gives a somewhat sensible answer, but for the love of god, someone answer!

Olegator [25]

It’s c Because is the one the makes the most sense

7 0

3 years ago

A 30.0-kgkg box is being pulled across a carpeted floor by a horizontal force of 230 NN , against a friction force of 210 NN . W

Agata [3.3K]

Answer:

The acceleration of the box is 0.67 m/s²

Explanation:

Given that,

Mass of box = 30.0 kg

Horizontal force = 230 N

Friction force = 210 N

We need to calculate the acceleration of the box

Using balance equation

$F-f_{k}=ma$

$a=\dfrac{F-f_{k}}{m}$

Where, F = horizontal force

$f_{k}$ =frictional force

m= mass of box

a = acceleration

Put the value into the formula

$a=\dfrac{230-210}{30}$

$a=0.67\ m/s^2$

Hence, The acceleration of the box is 0.67 m/s²

4 0

3 years ago

Pages 64 to 65 of your reading material trace an extended problem that involes lifting a bag of sugar up to a shelf at first it

nadezda [96]

Answer:

d) the amount of work is the same whether the bag is moved all at once or in two stages, provided the total height lifted is the same in either case.

Explanation:

While moving the bag to the shelf in one shot we can say that the total work done is given as

$W = mg(2H)$

here we know that

2H = total height raised by the bag

now when we raise the bag to first shelf and then move it to next shelf

then we will have

$W = W_1 + W_2[tex][tex]W = mgH + mgH$

$W = 2mgH$

so the correct answer will be

d) the amount of work is the same whether the bag is moved all at once or in two stages, provided the total height lifted is the same in either case.

7 0

3 years ago