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tangare [24]
2 years ago
5

A contact force exists between two interacting objects that physically contact each other. a non-contact force exists when two i

nteracting objects are not in physical contact but can still influence each other. true false
Physics
2 answers:
viva [34]2 years ago
8 0

Answer:

TRUE

Explanation:

Contact force is due to physical contact of two bodies

This force is due to interaction of two contact surfaces

This contact force is perpendicular to the surface at contact point always

Now for non contact force we know that two or more bodies can exert force on each other either by field force.

This field force can exert push or pull from distance when two bodies are not in contact with each other.

So the statement given here is TRUE

Murrr4er [49]2 years ago
4 0
True.

A contact force is a force between two objects that are physically in contact with each other: an example of a contact force is the normal reaction of a table supporting a book.

A non-contact force is a force between two objects that are not physically in contact with each other: an example of non-contact force is the gravitational attraction between the Earth and the Moon.
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Both atypical and traditional antipsychotics _____ levels of _____.
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Answer:

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3 years ago
Which term describes the forces acting on the car? A. inertial B. buoyant C. balanced D. unbalanced
Anna35 [415]
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3 0
3 years ago
1. What are three questions you should ask before joining a club?
lara [203]

Answer:

what time does it start.

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7 0
3 years ago
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strojnjashka [21]

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4 0
2 years ago
A plane accelerates from rest at a constant rate of 5.00 m/s2 along a runway that is 1800 m long. Assume that the plane reaches
tiny-mole [99]

Answer:

26.8 seconds

Explanation:

To solve this problem we have to use 2 kinematics equations: *I can't use subscripts for some reason on here so I am going to use these variables:

v = final velocity

z = initial velocity

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t = time

a = acceleration

{v}^{2}  =  {z}^{2}  + 2ax

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First let's find the final velocity the plane will have at the end of the runway using the first equation:

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