Humid air breaks down (its molecules become ionized) in an electric field of 4.99 x 10^6 N/C. In that field, what is the magnitu
1 answer:
Explanation:
It is given that,
Electric field,
The relation between the electric force and the electric field is given by :
Where
q is the charge
(a) Charge on the electron,
Electrostatic force,
(b) If an electron is missing, the net charge remains the same only sign changes.
So, force becomes,
Hence, this is the required solution.
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<u>In modern physics</u>, as it was called "Stefan-Boltzmann law", the total energy radiated per unit surface area of a black body is directly proportional to the fourth power of the black body's temperature T
as:
where: P is the power (total energy radiated per second per square meter) and T is the temperature of a black body.
then we can make a ratio between the state of before quadruple (with subscript 1) and after (with subscript 2) as:
As
Then
then
- The factor will the total energy radiated per second per square meter increase = 256
Answer:
λ = 3 10⁻⁷ m, UV laser
Explanation:
The diffraction phenomenon is described by the expression
a sin θ = m λ
let's use trigonometry
tan θ = y / L
as in this phenomenon the angles are small
tan θ = = sin θ
sin θ = y / L
we substitute
a y / L = m λ
let's apply this equation to the initial data
a 0.04 / L = 1 600 10⁻⁹
a / L = 1.5 10⁻⁵
now they tell us that we change the laser and we have y = 0.04 m for m = 2
a 0.04 / L = 2 λ
a / L = 50 λ
we solve the two expression is
1.5 10⁻⁵ = 50 λ
λ = 1.5 10⁻⁵ / 50
λ = 3 10⁻⁷ m
UV laser
Answer:
The correct question is:
"Find the energy each gains"
The energy gained by a charged particle accelerated through a potential difference is given by
where
q is the charge of the particle
is the potential difference
For a proton,
And since
The energy gained by the proton is
For an alpha particle,
Therefore, the energy gained is
Finally, for a singly ionized helium nucleus (a helium nucleus that has lost one electron)
So the energy gained is the same as the proton: