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Lana71 [14]
3 years ago
11

Humid air breaks down (its molecules become ionized) in an electric field of 4.99 x 10^6 N/C. In that field, what is the magnitu

de of the electrostatic force on (a) an electron and (b) an ion with a single electron missing? (a) Number _____ Units _____ (b) Number _____ Units _______
Physics
1 answer:
Zarrin [17]3 years ago
8 0

Explanation:

It is given that,

Electric field, E=4.99\times 10^6\ N/C

The relation between the electric force and the electric field is given by :

F=qE

Where

q is the charge

(a) Charge on the electron, q_e=-1.6\times 10^{-19}\ C

Electrostatic force,

F=-1.6\times 10^{-19}\times 4.99\times 10^6

F=-7.98\times 10^{-13}\ N  

(b) If an electron is missing, the net charge remains the same only sign changes.

So, force becomes, F=7.98\times 10^{-13}\ N  

Hence, this is the required solution.

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Which two types of simple machines can be found in a bicycle? lever and wheel and axle pulley and wedge wedge and wheel and axle
insens350 [35]

Answer:

A). A Lever and Wheel and Axle.

Explanation:

1. A wheel axle is most obvious, as the wheels are connected via a chain and axle with spokes. This helps keep the wheels moving forward with less effort than walking.

2. A Lever is used to help Balance you as you ride the bike. Without it, you would tip over, and lose all the momentum you had gained up until that point.

3. (I took the test on e2020)

5 0
3 years ago
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Is a vector necessarily changed if it is rotated through an angle ?​Explain
gavmur [86]
Yes, since it depends on the normal and resultant
6 0
3 years ago
A solid 0.4550 kg ball rolls without slipping down a track toward a vertical loop of radius R = 0.6750 m . What minimum translat
Talja [164]

Answer:

u = 3.35 m/s

Explanation:

given,

mass , m = 0.455 kg  

R = 0.675 m

Height of Loop = 1.021 m

the speed required at the top of loop be v

equating the force vertically

m g =\dfrac{mv^2}{r}

9.81 =\dfrac{v^2}{0.675}

v² = 6.622

v = 2.57 m/s

Let the initial speed of ball be u

using conservation of energy

\dfrac{1}{2}mu^2 + \dfrac{1}{2}I\omega^2 + m g h = \dfrac{1}{2}I\omega^2 + \dfrac{1}{2}mv^2+ m g (2 R)

where, I =\dfrac{2}{5}mr^2

\dfrac{1}{2}mu^2 + \dfrac{1}{2}(\dfrac{2}{5}mr^2)(\dfrac{u}{r})^2 + m g h = \dfrac{1}{2}(\dfrac{2}{5}mr^2)(\dfrac{v}{r})^2 + \dfrac{1}{2}mv^2+ m g (2 R)

0.7 u^2 + g H = 0.7 v^2 + g(2R)

0.7 u^2 +9.81 \times 1.021= 0.7\times 2.57^2 + 9.81 \times 2\times 0.675)

0.7 u² = 7.85092

u² = 11.2156

u = 3.35 m/s

the initial  speed is 3.35 m/s

8 0
3 years ago
8. A car travels at a constant velocity of 70 mph for one hour. By the end of the second hour, the car’s velocity was 60 mph. At
Mrac [35]

<u>Answer:</u>

  Positive acceleration is in third hour and negative acceleration is in second hour.

<u>Explanation:</u>

  Velocity of car in first hour =  70 mph

  Velocity of car in second hour = 60 mph

  Velocity of car in third hour = 80 mph

   Acceleration = Change in velocity / Time

   Acceleration in second hour = (60 - 70)/1 = -10 mph²

   Acceleration in third hour = (80 - 60)/1 = 20 mph²

   So positive acceleration is in third hour and negative acceleration is in second hour.

8 0
3 years ago
The magnitude of an electron's charge is e=1.60\times 10^{-19}\,\text{C}e=1.60×10 −19 Ce, equals, 1, point, 60, times, 10, start
Tresset [83]

Answer:

Explanation:

Conclusion is simple you can just say that it is the value written in words form only.

Nothing else is written about it

8 0
3 years ago
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