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MaRussiya [10]
3 years ago
8

Write a C program to calculate salary raise for employees. If salary is between$ 0 < $ 30000 the rate is 7.0%If salary is bet

ween$ 30000 <= $ 40000 the rate is 5.5%If salary is greater than$ 40000 the rate is 4.0%1. Let the user enter salary. Allow the user to enter as many salaries as the user wishes until the user enters a negative salary to quit. User can also decides to quite immediately after starting the program. Pick the proper loop.2. Calculate the raise, new salary, total salary, total raise, and total new salary.3. Sample input and output (leftmost column is user input): Salary Rate Raise New Salary Salary: 25000 25000.00 7.00 1750.00 26750.00 Salary: 30000 30000.00 5.50 1650.00 31650.00 Salary: 35000 35000.00 5.50 1925.00 36925.00 Salary 40000 40000.00 5.50 2200.00 42200.00 Salary: -1 Total 42200.00 7525.00 137525.00 Process returned 0 (0x0) execution time: 55.237 s Press any key to continue.
Computers and Technology
1 answer:
solmaris [256]3 years ago
5 0

Answer:

Written in C

#include <stdio.h>

int main(){

   float salary,rate,raise,newsalary,totalsalary = 0.0 ,totalraise = 0.0 ,totalnewsalary = 0.0;

   printf("Enter negative input to quit\n");

   printf("Salary: ");

   scanf("%f", &salary);

   while(salary>=0){

   if(salary>=0 && salary <30000){

       rate = 0.07;

   }

   else if(salary>=30000 && salary <=40000){

       rate = 0.055;

   }

   else{

       rate = 0.04;

   }

   

   raise = rate * salary;

   newsalary = salary + raise;

   totalraise +=raise;

   totalsalary+=salary;

   totalnewsalary+=newsalary;

   printf("Salary: %.2f\n", salary);

   printf("Rate: %.2f\n", rate);

   printf("Raise: %.2f\n", raise);

   printf("New Salary: %.2f\n", newsalary);

   printf("Salary: ");

   scanf("%f", &salary);

   }

   printf("Total Salary: %.2f\n", totalsalary);

   printf("Total New Salary: %.2f\n", totalnewsalary);

   printf("Total Raise: %.2f\n", totalraise);  

   return 0;

}

Explanation:

The declares all necessary variables as float

   float salary,rate,raise,newsalary,totalsalary = 0.0 ,totalraise = 0.0 ,totalnewsalary = 0.0;

This tells the user how to quit the program

   printf("Enter negative input to quit\n");

This prompts user for salary

   printf("Salary: ");

This gets user input

   scanf("%f", &salary);

The following iteration is repeated until user enters a negative input

   while(salary>=0){

This following if conditions check for range of salary and gets the appropriate rate of salary raise

<em>    if(salary>=0 && salary <30000){</em>

<em>        rate = 0.07;</em>

<em>    }</em>

<em>    else if(salary>=30000 && salary <=40000){</em>

<em>        rate = 0.055;</em>

<em>    }</em>

<em>    else{</em>

<em>        rate = 0.04;</em>

<em>    }    </em>

This calculates the raise by multiplying the salary by the rate of increment

   raise = rate * salary;

This calculates the new salary

   newsalary = salary + raise;

This calculates the total raise

   totalraise +=raise;

This calculates the total salary

   totalsalary+=salary;

This calculates the total new salary

   totalnewsalary+=newsalary;

This prints the salary

   printf("Salary: %.2f\n", salary);

This prints the rate of increment

   printf("Rate: %.2f\n", rate);

This prints the raise in salary

   printf("Raise: %.2f\n", raise);

This prints the new salary

   printf("New Salary: %.2f\n", newsalary);

This prompts user for salary input

   printf("Salary: ");

This gets user input for salary

   scanf("%f", &salary);

   } The while loop ends here

This prints the total salary

   printf("Total Salary: %.2f\n", totalsalary);

This prints the total new salary

   printf("Total New Salary: %.2f\n", totalnewsalary);

This prints the total raise in salary

   printf("Total Raise: %.2f\n", totalraise);  

   return 0;

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1)
spayn [35]

Answer:

1)

for(i = 0; i < NUM_VALS; ++i) {

  if(userValues[i] == matchValue) {

     numMatches++;  }    }

2)  

for (i = 0; i < NUM_GUESSES; i++) {

      scanf("%d", &userGuesses[i]);   }

  for (i = 0; i < NUM_GUESSES; ++i) {

         printf("%d ", userGuesses[i]);    }

3)

sumExtra = 0;

for (i = 0; i < NUM_VALS; ++i){

     if (testGrades[i] > 100){  

        sumExtra = testGrades[i] - 100 + sumExtra;    }       }

4)

for (i = 0; i < NUM_VALS; ++i) {

    if (i<(NUM_VALS-1))  

   printf( "%d,", hourlyTemp[i]);

    else  

    printf("%d",hourlyTemp[i]); }      

Explanation:

1) This loop works as follows:

1st iteration:

i = 0

As i= 0 and NUM_VALS = 4 This means for condition i<NUM_VALS  is true so the body of loop executes

if(userValues[i] == matchValue) condition checks if element at i-th index position of userValues[] array is equal to the value of matchValue variable. As matchValue = 2 and i = 0 So the statement becomes:

userValues[0] == 2

2 == 2

As the value at 0th index (1st element) of userValues is 2 so the above condition is true and the value of numMatches is incremented to 1. So numMatches = 1

Now value of i is incremented to 1 so i=1

2nd iteration:

i = 1

As i= 1 and NUM_VALS = 4 This means for condition i<NUM_VALS  is true so the body of loop executes

if(userValues[i] == matchValue) condition checks if element at i-th index position of userValues[] array is equal to the value of matchValue variable. As matchValue = 2 and i = 1 So the statement becomes:

userValues[1] == 2

2 == 2

As the value at 1st index (2nd element) of userValues is 2 so the above condition is true and the value of numMatches is incremented to 1. So numMatches = 2

Now value of i is incremented to 1 so i=2

The same procedure continues at each iteration.

The last iteration is shown below:

5th iteration:

i = 4

As i= 4 and NUM_VALS = 4 This means for condition i<NUM_VALS  is false so the loop breaks

Next the statement: printf("matchValue: %d, numMatches: %d\n", matchValue, numMatches);  executes which displays the value of

numMatches = 3

2)

The first loop works as follows:

At first iteration:

i = 0

i<NUM_GUESSES is true as NUM_GUESSES = 3 and i= 0 so 0<3

So the body of loop executes which reads the element at ith index (0-th) index i.e. 1st element of userGuesses array. Then value of i is incremented to i and i = 1.

At each iteration each element at i-th index is read using scanf such as element at userGuesses[0], userGuesses[1], userGuesses[2]. The loop stops at i=4 as i<NUM_GUESSES evaluates to false.

The second loop works as follows:

At first iteration:

i = 0

i<NUM_GUESSES is true as NUM_GUESSES = 3 and i= 0 so 0<3

So the body of loop executes which prints the element at ith index (0-th) index i.e. 1st element of userGuesses array. Then value of i is incremented to i and i = 1.

At each iteration, each element at i-th index is printed on output screen using printf such as element at userGuesses[0], userGuesses[1], userGuesses[2] is displayed. The loop stops at i=4 as i<NUM_GUESSES evaluates to false.

So if user enters enters 9 5 2, then the output is 9 5 2

3)

The loop works as follows:

At first iteration:

i=0

i<NUM_VALS is true as NUM_VALS = 4 so 0<4. Hence the loop body executes.

if (testGrades[i] > 100 checks if the element at i-th index of testGrades array is greater than 100. As i=0 so this statement becomes:

if (testGrades[0] > 100

As testGrades[0] = 101 so this condition evaluates to true as 101>100

So the statement sumExtra = testGrades[i] - 100 + sumExtra; executes which becomes:

sumExtra = testGrades[0] - 100 + sumExtra

As sumExtra = 0

testGrades[0] = 101

So

sumExtra = 101 - 100 + 0

sumExtra = 1

The same procedure is done at each iteration until the loop breaks. The output is:

sumExtra = 8

4)

The loop works as follows:

At first iteration

i=0

i < NUM_VALS is true as  NUM_VALS = 4 so 0<4 Hence loop body executes.

if (i<(NUM_VALS-1))   checks if i is less than NUM_VALS-1 which is 4-1=3

It is also true as 0<3 Hence the statement in body of i executes

printf( "%d,", hourlyTemp[i]) statement prints the element at i-th index i.e. at 0-th index of hourlyTemp array with a comma (,) in the end. As hourlyTemp[0] = 90; So 90, is printed.

When the above IF condition evaluates to false i.e. when i = 3 then else part executes which prints the hourlyTemp[3] = 95 without comma.

Same procedure happens at each iteration unless value of i exceeds NUM_VAL.

The output is:

90, 92, 94, 95

The programs along with their output are attached.

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3. A. is the answer, it is pre-consumer waste because the waste is from the manufacturing process. The waste is not from the consumer(whoever buys the product) so not B. and I doubt it is C. or D.

4. A. is the answer. Burning waste produces greenhouse gasses. B. can't be true, because the gasses from the burning are not the raw material. C. and D. couldn't be the case because water was not present in the disposal.

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Read 2 more answers
Create a function void process(char ch, int x, int y)- to accept an arithmetic operator (+,-./, in argum
saul85 [17]

Answer:

The program is as follows:

import java.util.*;

public class Main{

   public static void process(char ch, int x, int y){

if(ch == '+'){

    System.out.print(x+y);  }

else if(ch == '-'){

    System.out.print(x-y);  }

else if(ch == '*'){

    System.out.print(x*y);  }

else if(ch == '/'){

    if(y!=0){

        double num = x;

        System.out.print(num/y);      }

    else{

        System.out.print("Cannot divide by 0");     } }

else{

    System.out.print("Invalid operator"); }

 }

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 int x, y;

 char ch;

 System.out.print("Enter two integers: ");

 x = input.nextInt(); y = input.nextInt();

 System.out.print("Enter operator: ");

 ch = input.next().charAt(0);  

 process(ch,x, y);

}

}

Explanation:

The function begins here

   public static void process(char ch, int x, int y){

If the character is +, this prints the sum of both integers

<em> if(ch == '+'){</em>

<em>     System.out.print(x+y);  }</em>

If the character is -, this prints the difference of both integers

<em> else if(ch == '-'){</em>

<em>     System.out.print(x-y);  }</em>

If the character is *, this prints the product of both integers

<em> else if(ch == '*'){</em>

<em>     System.out.print(x*y);  }</em>

If the character is /, this prints the division of both integers.

<em> else if(ch == '/'){</em>

<em>     if(y!=0){</em>

<em>         double num = x;</em>

<em>         System.out.print(num/y);      }</em>

<em>     else{</em>

<em>This is executed if the denominator is 0</em>

<em>         System.out.print("Cannot divide by 0");     } }</em>

Invalid operator is printed for every other character

<em>else{</em>

<em>     System.out.print("Invalid operator"); }</em>

<em> </em> }

The main begins here

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

This declares both integers

 int x, y;

This declares the operator

 char ch;

Get input for both integers

<em>  System.out.print("Enter two integers: ");</em>

<em>  x = input.nextInt(); y = input.nextInt();</em>

Get input for the operator

<em>  System.out.print("Enter operator: ");</em>

<em>  ch = input.next().charAt(0);   </em>

Call the function

 process(ch,x, y);

}

}

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