You have to draw the numbers then you would have to divide them draw it
Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.
y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).
Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,
-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.
The equation of parabola y4 is y+4 = (1/4)x^2
Or you could elim. the fraction and write the eqn as 4y+16=x^2, or
4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.
Answer:
Let's begin with a 30°-60°-90° triangle. A 30°-60°-90° triangle with a hypotenuse of 2 um
Step-by-step explanation:
Step-by-step explanation:
if14a^2b/7a^2b answer is 2
and if the sign is addition then the answer is21a^2b if subtraction answer is7a^2b
Do this and then simplify the result
