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3 years ago

10

Use the number line to add the fraction. + + 1 1 7 3 -1 10 9 10 1 -1 10 4 5 3 5 Niat 1 2 + 1 5 N GIN 3 10 0 -1 3 10 1 10 + 1 2 +

7 10 2 5 3 5 4 5 9 10 10 10 5 Drag and drop the answer into the box to match the sum. - + 를 곪 10 2 9 10 - 1 10 1 10 를 곪 5 10

1 answer:

user100 [1]3 years ago

8 0

This is hard to understand , do u have a photo

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Graph the following linear function.<br> f(x) = 1/6x+3

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A quadratic rule for a particular parabola is of the form y = ax^2 + bx. The parabola passes through with the coordinates (-1, 4

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Answer:

y = (4/7)x² - (24/7)(x)

Step-by-step explanation:

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4 years ago

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Lesechka [4]

Answer:

Solution : $-\frac{3}{4}-\frac{3}{4}i$

Step-by-step explanation:

$-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]$

Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

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= $-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)$ ÷ $2\sqrt{2}\left(0-1\right)i$

= $3\left(-\frac{\sqrt{2}i}{2}+\frac{\sqrt{2}}{2}\right)$ ÷ $-2\sqrt{2}i$

= $\frac{3\left(1-i\right)}{\sqrt{2}}$ ÷ $2\sqrt{2}i$ = $-3-3i$ ÷ $4$ = $-\frac{3}{4}-\frac{3}{4}i$

As you can see your solution is the last option.

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3 years ago

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2 years ago

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