967.50 = 450 + 28.75p
967.50 - 450 = 28.75p
517.5 = 28.75p
18 = p
Answer:
The solutions are given below:
Step-by-step explanation:
x(x-3)+4(x²+2)
= x²-3x+4x²+8
= x²+4x²+8-3x
= 5x²+8-3x
2(a+5)-3(a+7)
= 2a+10-3a-21
= 2a-3a+10-21
= -a-11
xy(x²yz-xy²z+xyz²)
= x³y²z-x²y³z+x²y²z²
-4(a²-2a+8)
= -4a²+8a-32
<h3>
Hope it helps !</h3>
<h2>
The area of the framed photograph = 1156 
</h2>
Step-by-step explanation:
Given,
The length of photograph (l) = 14 inches and
The breadth of photograph (b) = 10 inches
To find, the area of the framed photograph = ?
We know that,
The area of the framed photograph = (l + 2b)(l + 2b)
= (14 + 2 × 10) (14 + 2 × 10) 
= (14 + 20) (14 + 20) 
= (34) (34) 
= 1156 
∴ The area of the framed photograph = 1156 
Answer:
9 units
Step-by-step explanation:
the y value doesnt change, so the distance from -5 to 4 is 9 units
Answer:B because i did the work and it’s it