2 years ago

Sue has 20 biscuits in a tin.

Mathematics

1 answer:

Julli [10]2 years ago

5 0

Answer:

$\frac{111}{190}$

Step-by-step explanation:

You might be interested in

Consider the geometric sequence: 3, 15, 75, 375, 1875 ... 1. What is the constant ratio, r, for this sequence? 2. Use r to write

zalisa [80]

R= 5

$a_{n} =3* 5^{n-1}$

7 0

3 years ago

Read 2 more answers

A shop owner bought 30 files and some diaries .he paid $82.50 for the files.each diary cost 10 times as much as a file.what was

Novay_Z [31]

<h3>✽ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ Divide total cost by the number of files:

82.50/30 = 2.75

Multiply by 10:

2.75 x 10 = 25.5

The cost was $27.50

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

7 0

3 years ago

If the measure of <8 is 112 degrees, the the m<6 = ?

WITCHER [35]

Answer:

112 Degrees

Step-by-step explanation:

Since 8 is 112 degrees, and 6 is opposite of 8, that means the measure of angle 6 is also 112 degrees

6 0

2 years ago

Read 2 more answers

Find an equation of the plane consisting of all points that are equidistant from (-3, 5, -4) and (-5, 0, 4), and having -2 as th

Firdavs [7]

Answer:

-2x-5y+8z+4.5=0

Step-by-step explanation:

Let (x,y,z) be the coordinates of the point lying on the needed plane. This point is equidistant from the points (-3, 5, -4) and (-5, 0, 4), so

$d_1=\sqrt{(x-(-3))^2+(y-5)^2+(z-(-4))^2}=\sqrt{(x+3)^2+(y-5)^2+(z+4)^2}\\ \\d_2=\sqrt{(x-(-5))^2+(y-0)^2+(z-4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\d_1=d_2\Rightarrow \sqrt{(x+3)^2+(y-5)^2+(z+4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\(x+3)^2+(y-5)^2+(z+4)^2=(x+5)^2+y^2+(z-4)^2\\ \\x^2+6x+9+y^2-10y+25+z^2+8z+16=x^2+10x+25+y^2+z^2-8z+16\\ \\-4x-10y+16z+9=0\\ \\-2x-5y+8z+4.5=0$

5 0

3 years ago

Read 2 more answers

Which of the following are interior angles in the figure below?

KATRIN_1 [288]

Answer:

(A), 21, 22,and 26

Step-by-step explanation:

gakzbzkxvuxnsslvzixvdkdbdjxvshhzvskdvxy dgsjzvsks ysjdbdudvsk jdkdbdb

7 0

3 years ago