Math please help !!!!!

Mathematics

1 answer:

bixtya [17]2 years ago

7 0

Answer:

hope it helped

Step-by-step explanation:

2nd one is the answer

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A rectangle has a perimeter of 32 in. find the length and width of the rectangle under which the area is the largest. follow the

Dafna1 [17]

Let width and length be x and y respectively.
Perimeter (32in) =2x+2y=> 16=x+y => y=16-x
Area, A = xy = x(16-x) = 16x-x^2
The function to maximize is area: A=16 x-x^2
For maximum area, the first derivative of A =0 => A'=16-2x =0
Solving for x: 16-2x=0 =>2x=16 => x=8 in
And therefore, y=16-8 = 8 in

5 0

3 years ago

When deriving the quadratic formula by completing the square, what expression can be added to both sides of the equation to crea

____ [38]

Answer:

According to steps 2 and 4. The second-order polynomial must be added by $-c$ and $b^{2}$ to create a perfect square trinomial.

Step-by-step explanation:

Let consider a second-order polynomial of the form $a\cdot x^{2} + b\cdot x + c = 0$ , $\forall \,x \in\mathbb{R}$ . The procedure is presented below:

1) $a\cdot x^{2} + b\cdot x + c = 0$ (Given)

2) $a\cdot x^{2} + b \cdot x = -c$ (Compatibility with addition/Existence of additive inverse/Modulative property)

3) $4\cdot a^{2}\cdot x^{2} + 4\cdot a \cdot b \cdot x = -4\cdot a \cdot c$ (Compatibility with multiplication)

4) $4\cdot a^{2}\cdot x^{2} + 4\cdot a \cdot b \cdot x + b^{2} = b^{2}-4\cdot a \cdot c$ (Compatibility with addition/Existence of additive inverse/Modulative property)