If this is your equation:

Solution:
LCD for 5 and 5x is 5x




←cross product
20x + 30 = 5x² + 25x ←simplify with distributive property
0 = 5x² + 5x - 30 ←use inverse operations to collect all terms on one side
0 = x² + x - 6 ←if possible divide by numerical GCF (This case 5)
0 = (x + 3)(x - 2) ←Factor
x = -3 or x = 2
Please check by substitution in original equation... Both work
To answer your question, it is shown in the image below:
B^-2 / b^-3 = b^(-2-(-3) = b^1 = b
answer is d
I believe it’s D but I’m not really sure hope this help a little
P=98 m
l +9=4w
p=2l+2w
98=2(4w-9) +2w
98 = 8w-18+2w
116=10w
w=11,6 m
l = 4w-9 = 4*11,6 -9 = 46,4 -9 = 37,4 m
w=11,6 m
l= 37,4 m