Ask question

Ask question

All categories

3 years ago

14

A video store charges $5 per game rental plus $12 to rent the game system. Write an expression for renting the game system and a

number of games

1 answer:

spin [16.1K]3 years ago

3 0

Y=5x+12
Y being the total amount and x being the number of games

You might be interested in

Can you please help me with this <br> 5/10 + 2/3<br><br> Thanks

Len [333]

Answer:

35/30

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

∆ABC is reflected about the line y = -x to give ∆A'B'C' with vertices

Semenov [28]

Well you have to change the first number in ALL of the () so

(-1,1) = (1,1)

(-2,-1) = (2,-1)

(-1,0) = (1,0)

so your answer is d <span>(1, 1), B(2, -1), C(1, 0)</span>

7 0

3 years ago

Read 2 more answers

Write the equation y-7= 2(x + 1) in standard form.

Andru [333]

Answer:

y=2X+9

Step-by-step explanation:

y-7=2(x+1)

Distribute 2 through: y-7=2x+2

Add 7 over to the other side: y=2x+9

4 0

2 years ago

Read 2 more answers

How many planes are shown in the figure?

grigory [225]

check the picture below.

8 0

3 years ago

Which expression is equivalent

gtnhenbr [62]

Answer:

Option B is correct.

$\frac{81m^2n^5}{8}$ is equivalent to $\frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}$

Step-by-step explanation:

Given expression: $\frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}$

Using exponents power:

$(ab)^n = a^nb^n$

$(a^n)^m = a^{nm}$

$a^m \cdot a^n = a^{m+n}$

Given: $\frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}$

Apply exponent power :

⇒ $\frac{3^4 (m^{-1})^4(n^2)^4}{2^3(m^{-2})^3 n^3}$

⇒ $\frac{81 m^{-4}n^8}{8m^{-6}n^3} = \frac{81 m^{-4} \cdot m^6 n^8 \cdot n^{-3}}{8}$

⇒ $\frac{81 m^{-4+6} n^{8-3}}{8} = \frac{81 m^2 n^5}{8} = \frac{81m^2 n^5}{8}$

Therefore, the expression which is equivalent to $\frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}$ is, $\frac{81m^2 n^5}{8}$

4 0

3 years ago

Read 2 more answers