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NNADVOKAT [17]
3 years ago
10

PLEASE HELP!! I've been stuck on this question for many days now and haven't found a correct answer! Thanks in advance!!!

Mathematics
2 answers:
stiv31 [10]3 years ago
7 0

Answer:

225% seems like the best answer.

Ivan3 years ago
3 0

The first time I did the math including 8 but we are increasing it so it will just be how much did the price increase from 8 to 18 well I know 100% of 8 is 8 so thats 100% and 25% of 8 is 2 so I added the two and 8 + 8 = 16 + 2 = 18 I added those percents 100 + 25 = 125%

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Rationalise the denominator of: (√3 + √2)/(√3-√2) = ?<br>​
krok68 [10]

Step-by-step explanation:

<h3><u>Given</u><u>:</u><u>-</u></h3>

(√3+√2)/(√3-√2)

<h3><u>To </u><u>find</u><u>:</u><u>-</u></h3>

<u>Rationalised</u><u> form</u><u> </u><u>=</u><u> </u><u>?</u>

<h3><u>Solution</u><u>:</u><u>-</u></h3>

We have,

(√3+√2)/(√3-√2)

The denominator = √3-√2

The Rationalising factor of √3-√2 is √3+√2

On Rationalising the denominator then

=>[(√3+√2)/(√3-√2)]×[(√3+√2)/(√3+√2)]

=>[(√3+√2)(√3+√2)]×[(√3-√2)(√3+√2)]

=>(√3+√2)²/[(√3-√2)(√3+√2)]

=> (√3+√2)²/[(√3)²-(√2)²]

Since (a+b)(a-b) = a²-b²

Where , a = √3 and b = √2

=> (√3+√2)²/(3-2)

=> (√3-√2)²/1

=> (√3+√2)²

=> (√3)²+2(√3)(√2)+(√2)²

Since , (a+b)² = a²+2ab+b²

Where , a = √3 and b = √2

=> 3+2√6+2

=> 5+2√6

<h3><u>Answer:-</u></h3>

The rationalised form of (√3+√2)/(√3-√2) is 3+2√6+2.

<h3><u>Used formulae:-</u></h3>

→ (a+b)² = a²+2ab+b²

→ (a-b)² = a²-2ab+b²

→ (a+b)(a-b) = a²-b²

→ The Rationalising factor of √a-√b is √a+√b

8 0
3 years ago
Translate the phrase into an inequality: <br> Seven plus a number x is at most twenty
Len [333]

At most means less than or equal to:

7 + x ≤ 20

3 0
3 years ago
A random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specime
MrRissso [65]

Answer:

We conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

We conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

Step-by-step explanation:

We are given a random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specimen;

1.10, 5.09, 0.97, 1.59, 4.60, 0.32, 0.55, 1.45, 0.14, 4.47, 1.20, 3.50, 5.02, 4.67, 5.22, 2.69, 3.98, 3.17, 3.03, 2.21, 0.69, 4.47, 3.31, 1.17, 0.76, 1.17, 1.57, 2.62, 1.66, 2.05.

Let \mu = <u><em>true average percentage of organic matter</em></u>

So, Null Hypothesis, H_0 : \mu = 3%      {means that the true average percentage of organic matter in such soil is 3%}

Alternate Hypothesis, H_A : \mu \neq 3%      {means that the true average percentage of organic matter in such soil is something other than 3%}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about the population standard deviation;

                         T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean percentage of organic matter = 2.481%

             s = sample standard deviation = 1.616%

            n = sample of soil specimens = 30

So, <u><em>the test statistics</em></u> =  \frac{2.481-3}{\frac{1.616}{\sqrt{30} } }  ~ t_2_9

                                     =  -1.76

The value of t-test statistics is -1.76.

(a) Now, at 10% level of significance the t table gives a critical value of -1.699 and 1.699 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics doesn't lie within the range of critical values of t, so we have <u><em>sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

(b) Now, at 5% level of significance the t table gives a critical value of -2.045 and 2.045 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have <u><em>insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

8 0
3 years ago
What is the measure of B (2n + 15) and D (3n - 5)? If ABCD is a parrallelogram
katovenus [111]

Answer : The value of angle B and angle D is 25⁰ and 35⁰ respectively.

Step-by-step explanation :

As we know that the opposite angles are equal in parallelogram.

According to the given figure,

∠A = ∠C

and

∠B = ∠D

Given:

∠B = (3n - 5)⁰

∠D = (2n + 15)⁰

From this we conclude that:

∠B = ∠D

(3n - 5)⁰ = (2n + 15)⁰

3n - 5⁰ = 2n + 15⁰

3n - 2n = 15⁰ - 5⁰

1n = 10⁰

n = 10⁰

∠B = (3n - 5)⁰ = (3×10 - 5)⁰ = 25⁰

∠D = (2n + 15)⁰ = (2×10 + 15)⁰ = 35⁰

Therefore, the value of angle B and angle D is 25⁰ and 35⁰ respectively.

5 0
3 years ago
SPHERE VOLUME
Arte-miy333 [17]
V = 4/3 * pi * r^3

V = 4/3 * 3.14 * 21^3

Simplify exponent:

V = 4/3 * 3.14 * 9261

Multiply:

V = 38772.72
6 0
4 years ago
Read 2 more answers
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