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2 years ago

PLEASE HELP!! I've been stuck on this question for many days now and haven't found a correct answer! Thanks in advance!!!

Mathematics

2 answers:

stiv31 [10]2 years ago

7 0

Answer:

225% seems like the best answer.

Ivan2 years ago

3 0

The first time I did the math including 8 but we are increasing it so it will just be how much did the price increase from 8 to 18 well I know 100% of 8 is 8 so thats 100% and 25% of 8 is 2 so I added the two and 8 + 8 = 16 + 2 = 18 I added those percents 100 + 25 = 125%

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Identify the initial amount a and the growth factor b in the exponential function

Olenka [21]

F(t)=1.4^t
a)a=1, b=0.4 
b)a=1.4, b=0<<<< 
c)a=1.4, b=t 
d)a=1, b=1.4
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3 years ago

Jane is X years old. How old will she be in 2 year's time? How old will she be in 5 year's time?

ch4aika [34]

Answer:

Jane's age = X

In 2 years time = X + 2

In 5 years time = X + 5

Step-by-step explanation:

Answer from Gauth math

6 0

2 years ago

Read 2 more answers

First question, thanks. I believe there should be 3 answers

zysi [14]

Given: The following functions

$A)cos^2\theta=sin^2\theta-1$ $B)sin\theta=\frac{1}{csc\theta}$ $\begin{gathered} C)sec\theta=\frac{1}{cot\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

To Determine: The trigonometry identities given in the functions

Solution

Verify each of the given function

$\begin{gathered} cos^2\theta=sin^2\theta-1 \\ Note\text{ that} \\ sin^2\theta+cos^2\theta=1 \\ cos^2\theta=1-sin^2\theta \\ Therefore \\ cos^2\theta sin^2\theta-1,NOT\text{ }IDENTITIES \end{gathered}$

$\begin{gathered} sin\theta=\frac{1}{csc\theta} \\ Note\text{ that} \\ csc\theta=\frac{1}{sin\theta} \\ sin\theta\times csc\theta=1 \\ sin\theta=\frac{1}{csc\theta} \\ Therefore \\ sin\theta=\frac{1}{csc\theta},is\text{ an identities} \end{gathered}$

$\begin{gathered} sec\theta=\frac{1}{cot\theta} \\ note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ tan\theta cot\theta=1 \\ tan\theta=\frac{1}{cot\theta} \\ Therefore, \\ sec\theta\ne\frac{1}{cot\theta},NOT\text{ IDENTITY} \end{gathered}$

$\begin{gathered} cot\theta=\frac{cos\theta}{sin\theta} \\ Note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ cot\theta=1\div tan\theta \\ tan\theta=\frac{sin\theta}{cos\theta} \\ So, \\ cot\theta=1\div\frac{sin\theta}{cos\theta} \\ cot\theta=1\times\frac{cos\theta}{sin\theta} \\ cot\theta=\frac{cos\theta}{sin\theta} \\ Therefore \\ cot\theta=\frac{cos\theta}{sin\theta},is\text{ an Identity} \end{gathered}$

$\begin{gathered} 1+cot^2\theta=csc^2\theta \\ csc^2\theta-cot^2\theta=1 \\ csc^2\theta=\frac{1}{sin^2\theta} \\ cot^2\theta=\frac{cos^2\theta}{sin^2\theta} \\ So, \\ \frac{1}{sin^2\theta}-\frac{cos^2\theta}{sin^2\theta} \\ \frac{1-cos^2\theta}{sin^2\theta} \\ Note, \\ cos^2\theta+sin^2\theta=1 \\ sin^2\theta=1-cos^2\theta \\ So, \\ \frac{1-cos^2\theta}{sin^2\theta}=\frac{sin^2\theta}{sin^2\theta}=1 \\ Therefore \\ 1+cot^2\theta=csc^2\theta,\text{ is an Identity} \end{gathered}$

Hence, the following are identities

$\begin{gathered} B)sin\theta=\frac{1}{csc\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

The marked are the trigonometric identities

3 0

1 year ago

An item has a listed price of $35 . If the sales tax rate is ,5% how much is the sales tax (in dollars)?

UkoKoshka [18]

Answer:

The sales tax is a 1.75.

Step-by-step explanation:

35 x 0.05 = 1.75

7 0

2 years ago

A guidance counselor randomly surveys 30 seniors about their post-high school plans. The table

bija089 [108]

Answer:

There is no table.

Step-by-step explanation:

Please attach it so I can answer!!

8 0

1 year ago