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3 years ago

6. A piece of solid gold was heated from 274K to 314K. 35.73 of energy was needed to raise the temperature.

1 answer:

5 0

From Q = mcΔT, we can rearrange the equation to solve for mass, m = Q/cΔT. The specific heat capacity, c, of solid gold is 0.129 J/g °C. I'm assuming that the energy is given in joules, as it's not specified in the question as written.

m = Q/cΔT = (35.73 J)/(0.129 J/g °C)(40.85 °C - 0.85°C)

m = 6.92 g of gold was present

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What’s the reaction type of aqueous magnesium sulfate + aqueous sodium carbonate?

IrinaK [193]

Answer: Double displacement reaction

Explanation:

Double displacement reaction is defined as the reaction where exchange of ions takes place.

The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

The chemical reaction between aqueous magnesium sulfate and aqueous sodium carbonate is represented as:

$MgSO_4(aq)+Na_2CO_3(aq)\rightarrow Na_2SO_4(aq)+MgCO_3(s)$

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2 years ago

What is the percent of hydrogen by mass in CH4O? (H:1.00 amu, C: 12.01 amu, O: 16.00 amu)

cricket20 [7]

The mass percent of hydrogen in CH₄O is 12.5%.

<h3>What is the mass percent?</h3>

Mass percent is the mass of the element divided by the mass of the compound or solute.

Step 1: Calculate the mass of the compound.

mCH₄O = 1 mC + 4 mH + 1 mO = 1 (12.01 amu) + 4 (1.00 amu) + 1 (16.00 amu) = 32.01 amu

Step 2: Calculate the mass of hydrogen in the compound.

mH in mCH₄O = 4 mH = 4 (1.00 amu) = 4.00 amu

Step 3: Calculate the mass percent of hydrogen in the compound.

%H = (mH in mCH₄O / mCH₄O) × 100%

%H = 4.00 amu / 32.01 amu × 100% = 12.5%

The mass percent of hydrogen in CH₄O is 12.5%.

Learn more about mass percent here:brainly.com/question/4336659

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2 years ago

How much water would need to be added to 1092 mL of a 54.7 M NaCl solution to make a 0.25 M solution?

babunello [35]

Answer:

237.8L of water would need to be added.

Explanation:

The first thing to do is to identify that the equation to be used is M1V1=M2V2. (This equation works because it turns everything into moles which can then be compared).

Then figure out what information you have and what is being found. In this case:

M1 = 54.7 M

V1 = 1092 mL = 1.092 L

M2 = 0.25 M

V2 = unknown

Then solve the equation for whatever you are trying to find.

M1V1=M2V2

V2=M1V1/M2

Now you need to plug everything in.

V2=(54.7M*1.091L)/0.25M

V2=238.93L

That means that the solution needs a volume of 238.7L to gain a molarity of 0.25M but the starting solution already had a volume of 1.092 L meaning that to find the amount of solvent that needs to be added you just subtract the starting volume by the volume that the solution needs to be.

238.93L - 1.091L = 237.8L

Therefore the answer is that 237.8L needs to be added to a 1.092L 54.7M NaCl solution to make the concentration 0.25M.

I hope this helps. Let me know if anything is unclear.

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2 years ago

What process created the sand and the soil?

Artist 52 [7]

Answer:

They are produced from rocks (parent material) through the processes of weathering and natural erosion.

Explanation:

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2 years ago

Read 2 more answers

Describe an element and a compound. Compare and contrast their similarities and differences. Identify how elements are related t

Alenkasestr [34]

Answer:

» Similarities :

☑ They both react by chemical means, to produce either an element or compound as the end product of the chemical reaction.

• Take an example of Magnesium reacting with cold water:

${ \rm{Mg_{(s)} + 2H _{2} O _{(l)} → Mg(OH)_{2(aq)} + H_{2(g)}}}$

• If it reacts with steam:

${ \rm{Mg _{(s)} + H _{2} O_{(l)} → MgO_{(s)} + H_{2(g)}}}$

• [ Element: Magnesium and Compound: Water ]

They are both classified under atomic substances cause they are made up of microscopic molecules known as atoms.

☑ They are both formed up by microscopic substances known as atoms.

» Differences :

☑ Compounds generally have higher molecular masses than elements.

☑ Compounds are formed through bonding by elements while elements can naturally exist or formed by extraction, purification and concentration

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1 year ago