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The structure of this oligopeptide is attached:
It consists of arginine - alanine - phenylalanine and leucine
From the picture we can see that N terminus charge is +1
Also Arginine is considered as basic amino acid with charge +1
C terminus charge is -1
At pH = 8, the whose pKa are less than pH will be deprotonated and the net charge will be +1
So the net charge of this oligopeptide is +1 at pH = 8
It consists of arginine - alanine - phenylalanine and leucine
From the picture we can see that N terminus charge is +1
Also Arginine is considered as basic amino acid with charge +1
C terminus charge is -1
At pH = 8, the whose pKa are less than pH will be deprotonated and the net charge will be +1
So the net charge of this oligopeptide is +1 at pH = 8
Answer:- 10 L of ethane.
Solution:- The given balanced equation is:
From this equation, ethane and oxygen react in 2:7 mol ratio, the ratio of volumes would also be same if they are at same temperature and pressure.
Since 14 L of each gas are taken, the oxygen will be the limiting reactant and ethane will be the excess reactant. Let's calculate the volume of ethane used:
=
From above calculations, 4 L of ethane are used. So, excess volume of ethane left after the completion of reaction = 14 L - 4 L = 10 L
Hence, 10 L of ethane will be remaining.