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krek1111 [17]
2 years ago
15

Giải thích tại sao chén sấy (hoặc chén nung) dùng chứa tủa phải xử lý cùng với điều kiện xử lý tủa? Thời gian sấy (hoặc nung) bắ

t đầu tính từ thời điểm nào? Giai đoạn sấy (hoặc nung) sau quá trình tạo tủa được gọi là giai đoạn gì? Sản phẩm của giai đoạn này được xử lý bước tiếp theo là gì trước khi thực hiện phép cân? Mục đích của bước xử lý này là gì?
Chemistry
1 answer:
nevsk [136]2 years ago
3 0
Hi how are you doing today Jasmine Jasmine
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One of the few xenon compounds that form is cesium xenon heptafluoride (CsXeF7). How many moles of CsXeF7 can be produced from t
larisa [96]
The balanced chemical equation is written as:

<span>CsF(s) + XeF6(s) ------> CsXeF7(s)

We are given the amount of </span>cesium fluoride and <span>xenon hexafluoride used for the reaction. We need to determine first the limiting reactant to proceed with the calculation. From the equation and the amounts, we can say that the limiting reactant would be cesium fluoride.  We calculate as follows:

11.0 mol CsF ( 1 mol </span>CsXeF7 / 1 mol CsF ) = 11.0 mol <span>CsXeF7</span>
6 0
3 years ago
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Based on the balanced equation 2C2H2 + 5O2 → 4CO2 + 2H2O calculate the number of excess reagent units remaining when 52 C2H2 mol
erica [24]

Answer:

20 molecules of oxygen gas remains after the reaction.

Explanation:

2C_2H_2 + 5O_2\rightarrow 4CO_2 + 2H_2O

Molecules of ethyne = 52

Molecules of oxygen gas = 150

According to reaction, 2 molecules of ethyne reacts with 5 molecules of oxygen gas.

Then 52 molecules of ethyne will react with:

\frac{5}{2}\times 52=130 molecules of oxygen gas.

As we can see that we have 150 molecules of oxygen gas, but 52 molecules of ethyne will react with 130 molecules of oxygen gas. So, this means that ethyne is a limiting reagent and oxygen gas is an excessive reagent.

Remaining molecules of recessive reagent = 150 - 130 = 20

20 molecules of oxygen gas remains after the reaction.

5 0
3 years ago
Balance the following:<br> _H2SO4 + _NaNO2 → _HNO2 + _Na2SO4
Alisiya [41]

Answer:

it is balanced

Explanation:

i solved it

4 0
3 years ago
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Which of the following is an example of a model?
Ivanshal [37]

Answer:

U

Explanation:

UUUUUUUUUUUUUU

8 0
3 years ago
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Naturally occurring neon exists as three isotopes. 90.51% is ne-20 with a mass of 19.99 amu, 0.27% is ne-21 with a mass of 20.99
gregori [183]

The atomic mass of an element is the average relative mass of its atoms as compared with an atom of carbon-12 whose mass is taken as 12. In terms of percentages of different isotopes, the average atomic mass can be determined as follows: A_{average} = ∑(p_{i}X A_{i})/100. Where, p_{i} is the percentage abundance of isotope with atomic number A_{i}.

So, average atomic mass of neon = \frac{(90.51 X 19.99) + (0.27 X 20.99) + (9.22 X 21.99)}{100} = 20.177 amu.

3 0
3 years ago
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