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Anika [276]
3 years ago
15

Carbon tetrachloride, once widely used in fire extinguishers andas a dry cleaning fluid, has been found to cause liver damage to

those exposed to its vapors over long periods of time. What is theboiling point of a solution prepared by dissolving 375 g of sulfur(S8, MW = 256.5g/mol) in 1250 g of CCl4?Kb = 5.05°C/m, boiling point ofpure CCl4 = 76.7°C)?A.70.8°C B.75.2°CC.78.2°CD.82.6°CE.>85°C
Chemistry
1 answer:
Svetradugi [14.3K]3 years ago
6 0

Answer:option D= 82.6°C

Explanation:

Step 1: determine the molality

Molality = moles of solute/ kg of solvent.

(Recall: number of moles= mass / molar mass).

Therefore, 375/256.5 g/mol = 1.4620 mole.

Substituting into the molality equation we have,

1.4620/ 0.1250kg = 11.696.

∆T(b) = k(b) × molality

∆T(b) = 82.6°C

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A block of metal has a width of 3.2 cm , a length of 17.1 cm , and height of 4.6 cm . Its mass is 1.4 kg . Calculate the density
dsp73

The Density of  the metal  is 5.6 g/cm³

<h3>What is the density of a substance?</h3>

The density of a substance is the ratio of the mass and the volume of the substance.

  • Density = mass/volume


The density of the metal is calculated as follows:

mass of metal = 1.4 kg = 1400 g

volume of metal = 3.2 * 17.1 * 4.6 = 251.712 cm³

Density of metal = 1400 g/251.712 cm³

Density of the metal  = 5.6 g/cm³

Therefore, the density of the metal is obtained from the mass and the volume of the metal.

Learn more about density at: brainly.com/question/1354972

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vova2212 [387]

Answer:

The limiting reactant is hydrogen, and the grams HCl produced is 36.175 g.

Explanation:

Balanced equation is 2 H + Cl2 = 2 HCl.

First thing, convert grams to moles via using molar mass.

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Next, determine which is the limiting reactant - probably the fastest way to do it is just to take one of the reactants, say it's the limiting one, and calculate how much of the other reactant would be needed if that really was the limiting reactant, and then compare it to the actual moles of reactant available.

If hydrogen was the limiting reactant at 0.992 mol, you'd need .496 mol of Cl2 to complete the reaction.

If chloride was the limiting reactant at 0.776 mol, you'd need 1.55 mol of H to complete the reaction.

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Once you've determined that, just plug in the amounts to the balanced equation to get the number of moles of HCL produced, which in this case, is just 0.992 mol.

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