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3 years ago

8

Anybody know chemistry Grahams law ?

1 answer:

sukhopar [10]3 years ago

7 0

There is two different types but i’ll just do both meanings just incase.

Graham's Law of Diffusion: the rate of diffusion of one gas through another is inversely proportional to the square root of the density of the gas.

Graham's Law of Effusion: the rate of effusion of a gas is inversely proportional to the square root of the density of the gas.

hopes this helps..!

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How many moles are in 48 molecules of H2O? What is the given amount?

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Answer:

1.635

Explanation:

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A 1.50 g sample of solid NH₄NO₃ was added to 35.0 mL of water in a styrofoam cup (insulated from the environment) and stirred un

GaryK [48]

Answer : The heat of the reaction is, 1.27 kJ/mole

Explanation :

First we have to calculate the heat released.

Formula used :

$Q=m\times c\times \Delta T$

or,

$Q=m\times c\times (T_2-T_1)$

where,

Q = heat = ?

m = mass of sample = 1.50 g

c = specific heat of water = $4.81J/g^oC$

$T_1$ = initial temperature = $22.7^oC$

$T_2$ = final temperature = $19.4^oC$

Now put all the given value in the above formula, we get:

$Q=1.50g\times 4.81J/g^oC\times (19.4-22.7)^oC$

$Q=-23.8095J=-0.0238kJ$

Now we have to calculate the heat of the reaction in kJ/mol.

$\Delta H=\frac{Q}{n}$

where,

$\Delta H$ = enthalpy change = ?

Q = heat released = 0.0238 kJ

n = number of moles NH₄NO₃ = $\frac{\text{Mass of }NH_4NO_3}{\text{Molar mass of }NH_4NO_3}=\frac{1.50g}{80g/mol}=0.01875mole$

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3 years ago

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Need help !!!!! Stuck

Leya [2.2K]

<h2>Hello!</h2>

The answer is:

The new pressure will be equal to 6 atm.

$P_{2}=6atm$

<h2>Why?</h2>

Since we know that the temperature is constant, we can use the Boyle's Law to solve the problem.

The Boyle's Law establishes that when the temperature is kept constant, the pressure and the volume will be proportional.

So, we have the equation:

$P_{1}V_{1}=P_{2}V_{2}$

We are given,

$P_{1}=2atm\\V_{1}=150mL\\V_{2}=50mL$

Substituting and isolating $P_{2}$ from the Boyle's Law, we have:

$P_{1}V_{1}=P_{2}V_{2}\\\\P_{2}=\frac{P_{1}V_{1}}{V_{2}}\\\\P_{2}=\frac{2atm*150mL}{50mL}=6atm$

Hence, the new pressure will be equal to 6 atm.

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