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yuradex [85]
3 years ago
15

Which function in vertex form is equivalent to f(x) = 4 + x2 – 2x?

Mathematics
1 answer:
Alexus [3.1K]3 years ago
6 0
<h3>Answer:</h3>

option A

f(x) = (x – 1)2 + 3

<h3>Step-by-step explanation:</h3>

Given in the question a function,

f(x) = 4 + x² – 2x

Step 1

f(x) = 4 + x² – 2x

here a = 1

        b = -2

        c = 4

Step 2

x = -b/2a

h = -(-2)/2(1)

h = 2/2

h = 1

Step 3

Find k

k = 4 + 1² – 2(1)

k = 3

Step 4

To convert a quadratic from y = ax² + bx + c form to vertex form,

y = a(x - h)²+ k

y = 1(x - 1)² + 3

y = (x - 1)² + 3

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Hi there! The answer is about 23%

First we need to find the total amount of buttered popcorn sold. This is 182 + 140 + 97 = 419 buckets.

To find the percentage of the buttered popcorn buckets that were large, we use the following formula:
\frac{part}{total} \times 100\%

Filling in this formula brings us to our answer:
\frac{97}{419} \times 100\% = 23.15
Hence, the answer is about 23%
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Answer:

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2 years ago
A manager of a grocery store wants to determine if consumers are spending more than the national average. The national average i
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The valid conclusions for the manager based on the considered test is given by: Option

<h3>When do we perform one sample z-test?</h3>

One sample z-test is performed if the sample size is large enough (n  > 30) and we want to know if the sample comes from the specific population.

For this case, we're specified that:

  • Population mean = \mu = $150
  • Population standard deviation = \sigma = $30.20
  • Sample mean = \overline{x} = $160
  • Sample size = n = 40 > 30
  • Level of significance = \alpha = 2.5% = 0.025
  • We want to determine if the average customer spends more in his store than the national average.

Forming hypotheses:

  • Null Hypothesis: Nullifies what we're trying to determine. Assumes that the average customer doesn't spend more in the store than the national average. Symbolically, we get: H_0: \mu_0 \leq \mu = 150
  • Alternate hypothesis: Assumes that customer spends more in his store than the national average. Symbolically H_1: \mu_0 > \mu = 150

where \mu_0 is the hypothesized population mean of the money his customer spends in his store.

The z-test statistic we get is:

z = \dfrac{\overline{x} - \mu_0}{\sigma/\sqrt{n}} = \dfrac{160 - 150}{30.20/\sqrt{40}} \approx 2.094

The test is single tailed, (right tailed).

The critical value of z at level of significance 0.025 is 1.96

Since we've got 2.904 > 1.96, so we reject the null hypothesis.

(as for right tailed test, we reject null hypothesis if the test statistic is > critical value).

Thus, we accept the alternate hypothesis that customer spends more in his store than the national average.

Learn more about one-sample z-test here:

brainly.com/question/21477856

3 0
1 year ago
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Answer:

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It has the same cross-section all along the shape from end to end; that means if you cut through it you would see the same 2D shape as on either end.

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Therefore, the function will be

R(t) = 10 + 0.50t

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