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ivolga24 [154]
3 years ago
12

4.In a hydroelectric power plant, 100 m3/s of water flows from an elevation of 120 m to a turbine, where electric power is gener

ated. The electric power you get out from the 80% efficiency turbine is known to be 50 MW, what is the rate of irreversible loss in the piping system (in MW unit)
Engineering
1 answer:
Dmitrij [34]3 years ago
4 0

Answer:

The rate of irreversible loss will be "55.22 MW".

Explanation:

The given values are:

Elevation,

h = 120 m

Flow of water,

Q = 100 m³/s

Efficiency,

= 80%

i.e,

= 0.8

Efficiency turbine,

= 50 MW

Now,

Without any loss,

The power generated by turbine will be:

⇒ P=\delta gQh

On substituting the values, we get

⇒     =1000\times 9.8\times 100\times 120

⇒     =117.72 \ MW

Power generated in actual will be:

= \frac{50}{0.8}

= 62.5 \ MW

Hence,

Throughout the piping system,

The rate of irreversible loss is:

= Power \ generated \ by \ turbine-Power \ generated  \ in \ actual

= 117.72-62.5

= 55.22 \ MW

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