The pressure gage on a 2.5-m^3 oxygen tank reads 500 kPa. Determine the amount of oxygen in the tank if the temperature is 28°C
1 answer:
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Answer:
For - 5.556 lb/s
For - 7.4047 lb/s
Solution:
As per the question:
System Load = 96000 Btuh
Temperature, T =
Temperature rise, T' =
Now,
The system load is taken to be at constant pressure, then:
Specific heat of air,
Now, for a rise of in temeprature:
Now, for :
Answer:
Explanation:
For pressure gage we can determine this by saying:
The closed tank with oil and air has a pressure of P₁ and the pressure of oil at a certain height in the U-tube on mercury is p₁gh₁. The pressure of mercury on the air in pressure gauge is p₂gh₂. The pressure of the gage is P₂.
We want to work out P₁-P₂: Heights aren't given so we can solve it in terms of height: assuming h₁=h₂=h
Answer:
hello your question is incomplete attached below is the missing part of the question
Consider an inverter operating a power supply voltage VDD. Assume that matched condition for this inverter. Make the necessary assumptions to get to an answer for the following questions.
answer : Nd ∝ rt
Explanation:
Determine how the delay and active power per device will change as the doping density of N- and P-MOSFET increases
Pactive ( active power ) = Efs * F
Pactive =
also note that ; Pactive ∝ Nd2 (
tD = K . since K = constant
Hence : Nd ∝ rt