Answer:
53%
Explanation:
To find the weight % in proeutectoid ferrite we use:
Wt % in proeutectoid ferrite=
[(0.80 - 0.39) / (0.80 - 0.02)] * 100=
= (0.41 /0.78) * 100 =
52.56%
which is approximately 53%
Answer:
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Answer:
269.1J
Explanation:
m = 12g
c = 0.897J/g°C
∆T = 45 - 20 = 25°C
H = mc∆T = 12 × 0.897 × 27 = 269.1J
Answer:
a. 4kg/s
b. 99.97 °C
Explanation:
Hello,
a. The resulting mass balance turns out into:

b. Now, the energy balance is:

In such a way, the first enthalpy is taken as a liquid-vapor mixture at 1 bar and 0.9 quality, it means:

Second enthalpy is taken by identifying that stream as an overheated vapor at 1 bar and 200 °C, thus, the resulting enthalpy is:

Then, the third enthalpy is taken by considering that at 95°C and 1 bar the water is a saturated liquid, thus:
.
Now, by solving for
, we've got:

Finally, by searching for that value of enthalpy, one sees that at 1 bar, the exiting stream is a liquid-vapor mixture that is at 99.97 °C and has a 72%- quality.
(NOTE: all the data was extracted from Cengel's book 7th edition).
Best regards.
Answer:
Relative roughness = 0.04
Explanation:
Given that:
Diameter = 5 cm
roughness = 2 mm
At inlet:
Minor coefficient loss 
At exit:
Minor coefficient loss 
Height h = 4m
Length = 5 m
To find the relative roughness:
Relative roughness is a term that is used to describe the set of irregularities that exist inside commercial pipes that transport fluids. The relative roughness can be evaluated by knowing the diameter of the pipe made with the absolute roughness in question. If we denote the absolute roughness as e and the diameter as D, the relative roughness is expressed as:


