Answer:
Find attached of the diagram that complete the question.
Velocity = 1.5 sec²θ m/s
Acceleration = 9 sec²θtanθ m/s²
Explanation:
Calculating the velocity:
V = dx/dt
x = 0.5tanθ
θ = 3t
ö = 3
V = d(0.5tanθ)/dt
= 0.5*sec²θ*ö
= 3*0.5sec²θ
= 1.5 sec²θ m/s
Calculating the acceleration, we have;
a = dv/dt
= d(1.5sec²θ)/dt
= 1.5*2sec²θtanθ*ö
= 1.5*2sec²θtanθ*3
= 9sec²θtanθ m/s²
Answer:
1064.8 kg/m³
Explanation:
Weight of the hydrometer = ρghA where ρ is the density, g is acceleration due to gravity, h is the submerged height and A is the cross sectional area.
W in water = ρwghwA
W in liquid = (ρliq)g hliq A where the cross sectional area is constant
W in water = W in liquid
(ρw)ghwA = (ρliq)g hliq A where ρw is density of water, ρliq is the density of liquid and hw and hliq are the heights of the liquid and that water. g acceleration due to gravity cancel on both sides as well as the constant A
pliq = × 1000 kg /m³ ( density of water) =(
) × 1000 = 1064.8 kg/m³