Answer:a) recovery factor = 53.3% ,bi) volume of oil per acre-ft = 11090.64bbl/acre-ft
bii) bulk volume of the reservoir in acre-ft = 1000 acre-ft
c) 62214.74 cubic feet
Explanation: a) recovery factor is the percentage amount of oil that can recovered from a reservoir, it is the oil produced divided by oil initially in place
Recovery factor= 1 - (Soi/1-Swi)
= 1 - (0.35/1-0.25)
= 0.533 × 100%
= 53.3%
bi) volume of oil which may be recovered per acre-ft = 7758.porosity.(1- Swi-Soi)
= 7758 x 0.2 x (1-0.25-0.35)
= 620.64 bbl/acre-ft
bii) bulk volume of the reservoir in acre-ft= Area x thickness
= 100 acres x 10 ft
= 1000 acre-ft
c) total volume of oil in cubic feet
since we have gotten volume as 1000 acre-ft we simply multiply it by the volume of oil gotten in answer bi)
= 1000 acre-ft x 620.64 bbl/ acre-ft
= 620640bbl
So we convert from barrel(bbl) to cubic feet, and 1 barrel is equal to 5.609 cubic feet, so to convert the answer from barrel to cubic feet we multiply the answer 620640 bbl by 5.609
= 620640 bbl x 5.609
= 3481580.711 cubic feet
The information gathered by the spiders is used to create a searchable index of the Web.
Answer: The total vehicle delay is
39sec/veh
Explanation: we shall define only the values that are important to this question, so that the solution will be very clear for your understanding.
Effective red time (r) = 25sec
Arrival rate (A) = 900veh/h = 0.25veh/sec
Departure rate (D) = 1800veh/h = 0.5veh/sec
STEP1: FIND THE TRAFFIC INTENSITY (p)
p = A ÷ D
p = 0.25 ÷ 0.5 = 0.5
STEP 2: FIND THE TOTAL VEHICLE DELAY AFTER ONE CYCLE
The total vehicle delay is how long it will take a vehicle to wait on the queue, before passing.
Dt = (A × r^2) ÷ 2(1 - p)
Dt = (0.25 × 25^2) ÷ 2(1 - 0.5)
Dt = 156.25 ÷ 4 = 39.0625
Therefore the total vehicle delay after one cycle is;
Dt = 39
