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3 years ago

385 x 42.13 x 0.079 is (consider significant figures):

Chemistry

1 answer:

Naddika [18.5K]3 years ago

4 0

385 x 42.13 x 0.079 = 1281.38395

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Plz help me out!!!!!

Lelu [443]

Answer:

i am not 100% sure but im pretty sure there is.

Explanation:

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2 years ago

Which of the following changes would improve the accuracy of the molar mass measurement carried out in this experiment:

aleksandrvk [35]

A. would not help and maybe make it harder to get accurate measurements.

b. would make more delta T which will improve its accuracy

c. will also increase delta T.

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3 years ago

Calculate the molarity of sodium ion in a solution made

Arada [10]

Answer:

0.1035 M

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Sodium chloride will furnish Sodium ions as:

$NaCl\rightarrow Na^{+}+Cl^-$

Given :

For Sodium chloride :

Molarity = 0.288 M

Volume = 3.58 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 3.58×10⁻³ L

Thus, moles of Sodium furnished by Sodium chloride is same the moles of Sodium chloride as shown below:

$Moles =0.288 \times {3.58\times 10^{-3}}\ moles$

Moles of sodium ions by sodium chloride = 0.00103104 moles

Sodium sulfate will furnish Sodium ions as:

$Na_2SO_4\rightarrow 2Na^{+}+SO_4^{2-}$

Given :

For Sodium sulfate :

Molarity = 0.001 M

Volume = 6.51 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 6.51 ×10⁻³ L

Thus, moles of Sodium furnished by Sodium sulfate is twice the moles of Sodium sulfate as shown below:

$Moles =2\times 0.001 \times {6.51\times 10^{-3}}\ moles$

Moles of sodium ions by Sodium sulfate = 0.00001302 moles

Total moles = 0.00103104 moles + 0.00001302 moles = 0.00104406 moles

Total volume = 3.58 ×10⁻³ L + 6.51 ×10⁻³ L = 10.09 ×10⁻³ L

Concentration of sodium ions is:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity_{Na^+}=\frac{0.00104406}{10.09\times 10^{-3}}$

The final concentration of sodium anion = 0.1035 M

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3 years ago

What is the percent composition of each element within the compound

kogti [31]

Answer:

The percentage composition of a given compound is defined as the ratio of the amount of each element to the total amount of individual elements present in the compound multiplied by 100. Here, the quantity is measured in terms of grams of the elements present.

please give me brainliest

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1 year ago

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In the presence of oxygen, the three-carbon compound pyruvate can be catabolized in the citric acid cycle. First, however, the p

Flura [38]

Answer:1.

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3 years ago