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Ganezh [65]
3 years ago
14

At 333 k, which of the pairs of gases below would have the most nearly identical rates of effusion?

Chemistry
1 answer:
rjkz [21]3 years ago
8 0
E. co and n2Effusion is the process where gas escapes through a hole. Gases with a lower molecular mass effuse more speedy than gases with a higher molecular mass. R<span>elative rates of effusion is related to the molecular mass.
a) M(N</span>₂)/M(O₂) = 28/32 = 0,875
b) M(N₂O)/M(NO₂) = 44/46 = 0,956
c) M(CO)/M(CO₂) = 28/44 = 0,636
d) M(NO₂)/M(N₂O₂) = 44/58= 0,758
e) M(CO)/M(N₂) = 28/28 = 1, <span>CO and N</span>₂ <span>have iexact molecular masses and will effuse at nearly identical rates.</span>
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El símbolo del ion que contiene 24 protones, 28 neutrones y 21 electrones es: (Marque con X la respuesta correcta)
mrs_skeptik [129]

Answer:

d) Cr⁺³

Explanation:

Consideremos un ion que contiene 24 protones, 28 neutrones y 21 electrones.

Para encontrar el simbolo del elemento, tenemos que considerar el número atómico (Z) que es igual al número de protones. Con esta información, buscamos en la tabla periódica el  elemento con Z=24 es el Cromo.

La carga total está dada por la diferencia entre protones y electrones. Los ´protones tienen carga +1 y los electrones carga -1. Luego, este ion tiene carga:

24 protones + 21 electrones = 24 . (1) + 21 . (-1) = +3

El simbolo del ion es Cr⁺³.

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2 years ago
What is the electron structure of sodium
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tino4ka555 [31]

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3 years ago
Elements within the same group of the periodic table behave similarly because they have the same number of ?
sammy [17]
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4 0
2 years ago
What is the empirical formula for a substance that is composed of 40.66% carbon, 8.53% Hydrogen,23.72% Nitrogen, and 27.09% Oxyg
prohojiy [21]

Answer:

THE EMPIRICAL FORMULA OF THE SUBSTANCE IS C2H5NO

Explanation:

The steps involved in calculating the empirical formula of this substance in shown in the table below:

Element                            Carbon           Hydrogen          Nitrogen         Oxygen

1. % Composition              40.66              8.53                 23.72                27.09

2. Mole ratio =

%mass/ atomic mass       40.66/12         8.53/1          23.72/14            27.09/16

                                       =  3.3883            8.53              1,6943             1.6931

3. Divide by smallest

value (0.6931)          3.3883/1.6931    8.53/1.6931    1.6943/1.6931   1.6931/1.6931

                               =      2.001                  5.038           1.0007                      1

4. Whole number ratio        2                       5                   1                               1

The empirical formula = C2H5NO

7 0
3 years ago
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