Answer: The molality of solution is 1.2 mole/kg
Explanation:
Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.
where,
n = moles of solute
= weight of solvent in kg
Given : 10 g of glycerol is present in 100 g of solution
moles of glycerol = ![\frac{\text {given mass}}{\text {molar mass}}=\frac{10g}{92g/mol}=0.108mol](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7Bgiven%20mass%7D%7D%7B%5Ctext%20%7Bmolar%20mass%7D%7D%3D%5Cfrac%7B10g%7D%7B92g%2Fmol%7D%3D0.108mol)
mass of water (solvent )= (100-10) = 90 g = 0.09 kg
Now put all the given values in the formula of molality, we get
Therefore, the molality of solution is 1.2 mole/kg
I think it's c if not then Google it
The answer is 546K. If you need the answer in degrees Celsius you subtract 273 from 546 and get 273 degrees Celsius. I included how I got the answer in the photo below. Hope this helps!
Answer:
C.) More NO₂ and SO₂ would form
Explanation:
Equilibrium:
This is the state of reaction in which the rate of forward reaction and reverse reaction are same.
There are three factors that effect the equilibrium condition.
The change in concentration
The change in volume
The change in temperature
In given equilibrium reaction,
SO₂ + NO₂ ⇄ NO + SO₃ + heat
when SO₃ is added it means more amount of product is on right side and equilibrium is disturb. Thus equilibrium is shifted toward the left produced more SO₂ and NO₂ and regain the equilibrium.
Answer:
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Explanation: